How many cubes are with two faces painted?

Number of cubes with three coloured face on the top side = 4
Number of cubes with three coloured face on the 2^nd from top side = 4
Number of cubes with three coloured face on the bottom side = 12
Total number of such cubes = 12 + 8 = 20

Number of cubes with no face painted is
105 - 34 - 24 - 20 = 27
Or else all the 3 x 3 x 3 inner cubes will remain coloured.

From top face (out of 3 x 3 square face) only one cubes is with one face painted.
From 4 vertical faces each face will give us 6 cubes hence total number of cubes from vertical faces is 6 x 4 = 24.
From bottom face we will get 3 x 3 = 9 cubes
So total number of cubes with one face painted is 1 + 24 + 9 = 34

Number of cubes removed from top face = 16
Number of cubes removed from bottom face = 4
Number of cubes left = 125 - (16 + 4 ) = 105

Initial total number of cubes = 343,
Number of cubes removed = 27
Smaller 27 cubes painted blue
Exposed faces of original big cube (3 faces with 9 cube on each face i.e total 27 cubes) painted with black
Out of 12 cubes in previous question there are 4 cubes with 2 faces yellow so number of cubes painted two faces only one with yellow and one with blue is 12 - 4 = 8

Here on each face 6 x 6 = 36 cubes that are painted with one colour.
Case (i): When red and blue are adjacent to each other then from one face we will get 6 x 6 = 36 cubes but out of them 6 cubes from common edge is common so number of cubes are 2 x 6 x 6 - 6 = 66
Case (ii): When red and blue are opposite to each other then required number of cubes is 2 x 6 x 6 = 72

Here on each face 6 x 6 = 36 cubes that are painted with one colour.
Case (i): when these three colour are adjacent to each other then from one face we will get 6 x 6 = 36 cubes but out them 6 x 3 = 18 cubes from common edge is common so number of cubes are 3 x 6 x 6 - 6 x 3 = 90
Case (ii): When red and blue are opposite to each other (or any two of the given three) then required number of cubes is 3 x 6 x 6 - 2 x 6 = 96

Here on each face 6 x 6 = 36 cubes that are painted with one colour.
Case (i): When red and blue are opposite to each other then from one face we will get 6 x 6 = 36 cubes bot out of them 2 x 6 cubes from common edge with green painted face is common so number of cubes are 2 x 6 x 6 - 2 x 6 = 60
Case (ii): When red and blue are adjacent to each other then green is either adjacent to these or opposite to any one of red or blue, in 1^st condition number of cubes is 2 x 6 x 6 - 2 x 6 - 11 = 55 cubes or in 2^nd condition 2 x 6 x 6 -6 - 6 = 60, required number of cubes is 55 or 60

Here on each face 6 x 6 = 36 cubes that are painted with one colour.
From solution of previous questions statements (ii) and (iii) are correct.

Here on each face 6 x 6 = 36 cubes that are painted with one colour.
None of the cubes can be painted in four faces.