Let us see the changes due to removal of cube from corner-
Number of vertices with three faces exposed (Painted) is 7 + 3 = 10
Number of Cubes with 2 sides exposed (Painted): In general one edge gives us 4 (n - 2 in general case) cubes with two face painted but in this case out of 12 edges only 9 edges will give us 4 cubes in one edge and remaining 3 edges will give us 3 cubes from one edge, hence total number of edge is 9 x 4 + 3 x 3 = 45
Number of Cubes with 1 side exposed (Painted): It will remain same as normal case i.e. 6(42) = 96
Number of Cubes with no sides exposed (Painted) is 43 = 64
From the above observation:
From the above explanation number of the cubes with at most 2 faces painted is 64 + 96 + 45 = 205.
Or else 215 - 10 = 205
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On the basis of given figures in above question , we can see that
In each subsequent figure the design rotates through 90° anticlockwise.
Hence , figure ( 1 ) will come on the place of ? in question figure . As shown in answer figures .
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Answer figure (2) can be formed from the cut-pieces given in the question figure.
As per the given figure in above question, it is clear that
In each subsequent figure the number of asterisks is increasing by one and the lower circle moves from left to right and vice-versa.
Clearly , figure ( 3 ) will come on the place of ? from answer figures .
Answer Figure (1) can be constructed from the parts given in question figure.
After opening the first fold it will look like as:
When it is unfolded completely it will look like as:
In this question, the sets of numbers given in the alternatives are represented. The columns and rows of Matrix I are numbered from 0 to 4 and that of Matrix II are numbered from 5 to 9. A letter from these matrices can be represented first by its row and next by its column, e.g., 'K' can be represented by 41,34, etc., and 'Z' can be represented by 75, 86, etc. Similarly you have to identify the set for the word 'PAWN'.
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