Out of 6 faces of 4 faces are exposed and those were painted.
Number of vertices with three faces exposed (Painted) is 2
Number of vertices with 2 faces exposed (Painted) is 4
Number of vertices with 1 faces exposed (Painted) is 2
Number of vertices with 0 faces exposed (Painted) is 0
Number of sides with 2 sides exposed (Painted) is 5
Number of sides with 1 sides exposed (Painted) is 6
Number of sides with no sides exposed (Painted) is 1
From the above observation:
Number of cubes with 3 faces Painted is 2
Number of cubes with 2 faces Painted is given by sides which is exposed from two sides and required number of cubes is 6 x 4 + 1 x 5 = 29 since there are 4 edges will give us 6 cubes from 1 edge and 1 edge (between two vertices which are painted or exposed from 3 sides) will give us only 5 cubes.
Number of cubes with 1 face Painted is given by faces which is exposed from one sides and required number of cubes is 36 x 2 + 30 x 2 = 132
Number of cubes with 0 face Painted is given by difference between total number of cubes - number of cubes with at least 1 face painted = 343 - 2 - 29 - 132 = 180
In other words number of cubes with 0 painted is 6 x 6 x 5 =180
From the above explanation number of the cubes with at most 2 faces painted is
180 + 132 + 29 = 341.
Or else 343 - 2 = 341
On the basis of above given question figures , we can see that
In each subsequent figure the line segment rotates 90° clockwise and two arrow heads are added to both ends, one to each end.
Hence , required answer will be option B .As shown in above given answer figures .
From first unit to second unit the triangle rotates through 90° clockwise and moves to the side of square and a similar triangle appears on the opposite side.
The element in the first two figure changes its position diagonally and central figure remains same.
As per the given figure in above question, it is clear that
In each subsequent figure one line segment is added in a set order.
Thus , figure ( 3 ) will come on the place of ? in question figure .As shown in answer figures .
Answer C
On the basis of given figure in above question,we get
From first figure to second figure the upper figure is inverted and the lower figure moves inside it. The line segments of the upper figure are arranged in a set order.
Hence , figure ( 3 ) will come on the place of ? from answer figures .
On the basis of given figures in above question , we can see that
In each subsequent figure one vertical and two horizontal line segments are added in a set order.
Hence , figure ( 4 ) will come on the place of ? from answer figures .
All the elements of the top row moves to second row, second row elements move to third row and third row elements move to first row.
As per the given above question figures , we can see that
In each subsequent figure the ribs of leaf are inverted and some parts of flower are deleted.
Therefore , figure ( 4 ) will come on the place of ? in question figure .As shown in answer figures .
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