How many of the cubes have at most faces painted?

Out of 6 faces of 4 faces are exposed and those were painted.
Number of vertices with three faces exposed (Painted) is 2
Number of vertices with 2 faces exposed (Painted) is 4
Number of vertices with 1 faces exposed (Painted) is 2
Number of vertices with 0 faces exposed (Painted) is 0
Number of sides with 2 sides exposed (Painted) is 5
Number of sides with 1 sides exposed (Painted) is 6
Number of sides with no sides exposed (Painted) is 1
From the above observation:
Number of cubes with 3 faces Painted is 2
Number of cubes with 2 faces Painted is given by sides which is exposed from two sides and required number of cubes is 6 x 4 + 1 x 5 = 29 since there are 4 edges will give us 6 cubes from 1 edge and 1 edge (between two vertices which are painted or exposed from 3 sides) will give us only 5 cubes.
Number of cubes with 1 face Painted is given by faces which is exposed from one sides and required number of cubes is 36 x 2 + 30 x 2 = 132
Number of cubes with 0 face Painted is given by difference between total number of cubes - number of cubes with at least 1 face painted = 343 - 2 - 29 - 132 = 180
In other words number of cubes with 0 painted is 6 x 6 x 5 =180
From the above explanation number of the cubes with at most 2 faces painted is
180 + 132 + 29 = 341.
Or else 343 - 2 = 341