Classification (words – vowels): Three words contain exactly one vowel; one word contains two vowels. Identify the odd word.
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ADOG
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BFED
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COUT
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DDIN
Answer
Correct Answer: OUT
Explanation
Introduction / Context:Word-classification often uses simple letter features. Here, each option is a three-letter English word. The criterion is the count of vowels (A, E, I, O, U). Three have exactly one vowel; one has two. The task is to pick the outlier with two vowels.
Given Data / Assumptions:
- DOG → vowels: O (1).
- DIN → vowels: I (1).
- FED → vowels: E (1).
- OUT → vowels: O, U (2).
Concept / Approach:Count vowels in each word and compare. The unique case with two vowels is the odd one out.
Step-by-Step Solution:
Scan each word; tally vowels.DOG, DIN, FED each contain a single vowel.OUT contains two vowels (O and U).Verification / Alternative check:Check consonant count: the outlier has only one consonant (T), whereas the others have two consonants each.
Why Other Options Are Wrong:
They share the same single-vowel pattern.Common Pitfalls:Overcomplicating with alphabetic positions. The test here is a straightforward vowel count.
Final Answer:OUT