Number of matches in stage 1 is 2(7 x 8/2) = 56, at semifinal stage we have 3 matches (2 semifinal and 1 match for 3rd place) and 1 final match, hence total number of matches is 56 + 3 + 1 = 60
If G played with B in semifinal round then H lost both the matches against B in the stage 1
A lost both the matches to B or H not B and H hence option C is incorrect.
E lost the maximum number of matches.
2nd Highest is either B or H so cant determine.
option (a) is correct
Seed 9 will play with seed, 1, 3, 5, 7, 11, 13, and 15 without an upset seed 9 can with seed 11, 13, and 15, for minimum number of upset let seed 1 won all the matches and seed 9 won against seed 3 and 5, in that case number of wins of seed 3 and 9 is 5 but with tie breaker rule seed 9 will advance to the next stage.
Total number of matches is 60 and out of those more than 45 matches are upset. But seed 1 need only 9 matches to win the tournament hence seed 1 may win the tournament.
Total number of matches in the 1st stage is 4 x 7 = 28, lets consider group 1 here if seed 1 won all the matches then remaining 21 matches or points can be equally distributed to 7 player (3 points each) and the lowest possible player would advance to next stage with tie breaker rule. In this stage seed 13 can get 3 points after 2 upsets caused by him. So from this group seed 1 and 13 would advance to the next stage. Similarly from 2nd group seed 2 and 14 would advance to the next stage.
Now as per the rule seed 1 will play with seed 14 and seed 2 will play with seed 13,
If seed 13 and 4 meet in the tournament then seed 13 will win with 3 upset.
Bhanu
he needs 6 wins
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