Minimum is 6 and maximum is 10 represented by option
No player can win 3 matches
From the table any option can satisfy the given condition.
from table option (c) is correct.
For minimum number of matches lets take example of R4 he won 0 matches in stage 1 and 5 matches in stage II. So required minimum number is 5.
Total number of matches is 21 when divided in 3 stages we will get 7 matches in one stage.Hence , required answer is Bhanu.
The new result will be as follows :
Number of matches in Stage 1 is 2(8C2) = 2(7 x 8/2) = 56
stage 2 will be a knockout tournament with 8 teams so in this stage number of matches will be 7.
Total number of matches is 56 + 7 = 63
In the 1st round in one group number of matches is (7 x 8/2) = 2
Lets consider bottom 3 they will have 3 matches between them, so remaining 28 - 3 = 25 matches have involvement of top 5 teams, if they won equal number of matches i.e 5 each then decision will be taken based on tie breaker rule, hence a team may be eliminated even after winning 5 matches.
From the solution of previous question even after winning 5 matches a team can get eliminated so to be sure a team must win 6 matches.
Consider top three team if they won maximum number of matches then points with them is 7 + 6 + 5 = 18, remaining 28 - 18 = 10 points can be distributed to bottom 5 teams, so even after getting 2 points or 2 wins a team can advanced to next stage by tie breaker rule.
From the solution of previous question a team even with two wins can advanced to next stage where it has to play 3 matches so total number of matches is 5.
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