How many matches G lost?

From the table F won 4 matches.

From the solution of previous question we have seen that seed 32 can win the tournament without causing an upset by him. So seed 15 can also win the tournament without causing an upset by him.

If all the matches in stage 1 is an upset except the last match where seed 32 won, then in stage 2 seed 32 is the highest seeded player who can win the tournament without causing an upset.

Seed 9 played with seed 56 in stage 1, with seed 24 in stage 2, But seed 11 can reach the final if he beats seeds 6, 3 and 2 in stage 3 4 and 5 respectively.

Total number of matches is 32 + 16 + 8 + 4 +2 + 1 = 63
Or else since total number of players is 64 hence number of matches must be 64 - 1 = 63

From the table E won against C and G

C and E won 2 matches.

2 teams won 2 matches each

From the given conditions we can form the table as follows:
From the table we can conclude that Karnataka and Punjab have 1 match to play against each other. It is also given that A win can fetch 2 points, and a loss, 0 point.
The maximum points that Gujrat (with lowest point) = 18 + ( 5 × 2 ) = 28 and he may not be eliminated, Similarly there are certain conditions exist where every team has a chance to survive.

First Stage: There is two groups of 8 teams each. In each group, each team plays with every other team and hence total number of matches are ⁸c₂ = 8 × ( 7/2 ) = 28 matches So, in both the groups the total number of matches played at the first stage are 28. And hence 56 matches are played in 1^st stage
Second Stage: In this stage there are 8 teams playing in such a way that in one round 4 teams play with 4 other teams. 4 teams win and go to the next round. That is called knock out tournament.
In the 1^st round no of matches ( 8/2 ) = 4,
In the 2^nd round no of matches = ( 4/2 ) = 2,
In the third or the last round number of match = ( 2/2 ) = 1,
So , total no. of matches in 2^nd stage is 4 + 2 + 1 = 7
Hence total match in the tournament = 56 + 7 = 63