One year ago, the ratio of Yamini and Gamini's was 6 : 7 respectively. Four year hence, the ratio would become 7 : 8. Find the age of Gamini?

The ratio of Ram's and Mohan's present age is 7 : 5.
Let us assume the present ages of Ram and Mohan are 7Y and 5Y years.
2 Years ago the age of Ram and Mohan will be 7Y - 2 and 5Y - 2 years.
According to question,
Two years ago, the ratio of Ram's and Mohan's age was 3 : 2, then
(7Y -2)/(5Y - 2) = 3/2
? (7Y -2) x 2 = 3 x (5Y - 2)
? 14Y - 4 = 15Y - 6
? Y = 2
Hence, their present ages = 7 x 2 = 14 years and 5 x 2 = 10 year

Let us assume the present age of Radha be Y years; then
Before 6 years Radha's age will be Y - 6 years.
According to question,
Today her age is 1¹/₄ times her age at the time of marriage,
5/4 ( Y - 6 ) = Y ( Since 1¹/₄ = 5/4 )
? 5Y - 30 = 4Y
? Y = 30 years
Hence, her son's age = 30 x 1/10 =3 years

Method 1
Let the present age of B and A be x and ( x + 9 ) years; then,
Age of B and A after 10 years will be x + 10 and x + 9 + 10;
According to question,
In 10 years A will be twice as old as B was 10 years ago
2(x - 10) = x + 9 + 10
2x - 20 = x + 19
? 2x - x = 19 + 20
? x = 39 years

Method 2
Let us assume the present age of B and A be x and y years.
According to question,
A is now 9 years older than B,
y = x + 9...........(1)
Again according to question,
In 10 years A will be twice as old as B was 10 years ago
y + 10 = 2( x - 10)................. (2)
now put the value of y from equation (1) in above equation (2)
x + 9 +10 = 2x - 20
? 2x - x = 19 + 20
? x = 39 years
So Present age of B = 39 years.

Let us assume the ages of A and B be 3x and 11x years; then
After 3 years the ages of A and B will be 3x + 3 and 11x + 3.
According to question,
After 3 years the ratio of the ages becomes 1: 3,
(3x + 3)/(11x + 3) = 1/3
? 3 (3x + 3) = 1 (11x + 3)
? 9x + 9 = 11x + 3
? 2x = 6
? x = 3
Hence, their present age, 3x = 3 x 3 = 9 years; 11x = 11 x 3 =33 years

The word which cannot be formed from 'SPECIFICATION' is 'FAINTING', because 'G' is not present in given word.

Let the present ages of Surabhi and Neerja are 6x and 7x years respectively.
According to question,
(6x + 6)/(7x + 6) = 15/17
? (6x + 6)x17 = 15x(7x + 6)
? 102x + 102 = 105x + 90
? 3x = 12
? x = 4
Hence, present ages of Neerja = 7 x 4 = 28 years

Let us assume the present ages of woman and her daughter be 2x and x years respectively ; then
According to question,
The average age of a woman and her daughter is 42 years
(2x + x)/2 = 42
? 3x = 84
? x = 28
Hence, present age of her daughter = 28 years

Let the present ages of A and B are 11x and 13x years respectively; then
According to question,
After 7 years the ratio of their ages will be 20 : 23.
(11x + 7 ) / (13x + 7) = 20/23
? (11x + 7 ) 23 = 20 (13x + 7)
? 253x + 161 = 260x + 140
? 7x = 21
? x = 3
Hence, difference of their ages = 13x - 11x = 2x = 2 x 3 = 6 years

Let the present ages of A, B and C are 3x, 5x and 7x years respectively; then
According to question,
3x + 5x + 7x = 3 x 25
? 15x = 75
? x = 5
Hence, age of A = 3x = 3 x 5 = 15 years

Let us assume the present age of baby Y year.
According to question,
Three years ago, the average age of a family of 5 members was 17 years.
The present Total age of the family of 5 member = 5 x 17 + 5 x 3 =100 ..........(1)
Again according to question,
The average age of the family is the same as what was three years ago.
The present average age of family of 6 member= 17
Total present age of family of 6 member / 6 = 17
(Total present age of family of 5 member + present age of baby)/6 = 17
100 + Y = 17 x 6
Y = 17 x 6 - 100 = 102 - 100 = 2 years