Given that their salaries are in the ratio of 3:4 and expenditure is in the ratio of 4:5 hence we can assume that salary of A and B are 3x and 4x and their expenditures are 4y and 5y.
Now we need to find the ratio of (3x - 4y)/(4x - 5y)
Consider statement I alone:
Giving of B is 25% of his salary hence his expenditure must be 75% so 3/4(4x) = 5y or 3x = 5y from this we can find the required ratio hence this statement is sufficient.
Consider statement II alone :
Given that 4x = 2000 or x = 500 but from this we can not find the value of y and hence we can not find the ratio of their savings.
Required percentage = 7020 - 3210 x 100 = 118.69%
Given relationship is (PQ)(RQ) = XXX
Since X can take 9 values from 1 to 9 hence we have 9 possibilities
111 = 3 x 37 444 = 12 x 37 777 = 21 x 37
222 = 6 x 37 555 = 15 x 37 888 = 24 x 37
333 = 9 x 37 666 = 18 x 18 999 = 27 x 37
But out of these 9 cases only in 999, we get the unit's digit of two numbers the same. Since it is a unique value, hence we need neither statement I nor statement II to answer the question.
As per given Table graph,
Rice produced by state C in years 2006 = 1300
Rice produced by state A in years 2006 = 1700
Required percentage = 1300 x 100 /1700 = 76.47% ? 76%
Total number of female employee = 13363
Required average number of females = 13363/6 = 2227.16
Approx 2227
From above graph ,
Since , In July and August months did all the commodities show decline or no increase from the previous months.
Required answer will be July and August only .
Number of employees working in different organisation are
A ? 1050 + 1017 + 1382 + 1542 + 786 + 48 = 5825
B ? 1015 + 960 + 1384 + 1545 + 745 + 54 = 5703
C ? 976 + 786 + 1275 + 1550 + 801 + 36 = 5424
D ? 888 + 1025 + 1300 + 1570 +800 + 30 = 5613
E ? 1004 + 963 + 1290 + 1580 + 735 + 53 = 5625
Hence, total number of employees = 5825 + 5703 + 5424 + 5613 + 5625 = 28190
In 2008, number of students in Engineering = Total Student x 18%
In 2008, the number of students in Engineering = 35000x18/100 = 6300
In 2009, number of students in Engineering = Total Student x 19%
In 2009, the number of student in Engineering =40000 x19/100 = 7600
Required percentage = (number of students in Engineering in 2009 - number of students in Engineering 2008) x 100 / number of students in Engineering in 2008
Required percentage = (7600 - 3600)x 100 /6300 = 1300/63 = 20.6 ? 20%
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