Discussion
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- Question
- Who among P, Q, R, S and T is the tallest?
I. P is taller than Sand T but shorted than R, Q is taller than S.
II. T is taller than S. P is not the tallest.
Options- A. if the data in Statement I alone are sufficient to answer the question, while the data in Statement II alone are not sufficient to answer the question.
- B. if the data in Statements II alone are sufficient to answer the question, while the data in Statement I alone are not sufficient to answer the question.
- C. if the data either in Statement I alone or in Statement II alone are sufficient to answer the question.
- D. if the data given in both the Statement I and II together are not sufficient to answer the question.
- Correct Answer
- if the data given in both the Statement I and II together are not sufficient to answer the question.
ExplanationEven by using both the statements, we are not able to detemine who is tallest as we do not have the exact idea about the height of Q.
- 1. If the total amount spent during the year was $ 1,20,00,000 how much was spent on basketball?
Options- A. $ 12,50,000
- B. $ 10,00,000
- C. $ 12,00,000
- D. $ 15,00,000 Discuss
- 2. The total number of students who come to school by car is:
Options- A. 70
- B. 290
- C. 420
- D. 480 Discuss
- 3. Which car is 40% more popular than black cars?
Options- A. Blue
- B. Brown
- C. Red
- D. Sliver Discuss
- 4. The percentage of students failed in 1984 was
Options- A. 18 1 % 2
- B. 17 3 % 4
- C. 17 1 % 2
- D. 17% Discuss
- 5. What is the percent increase in the number of products sold by the company in the year 2006 from the previous year? (Rounded off to two digits after decimal)
Options- A. 19.25
- B. 33.33
- C. 10.45
- D. 42.66 Discuss
- 6. The ratio of the total amount of money spent on housing to that spent on education was :
Options- A. 5 : 2
- B. 2 : 5
- C. 4 : 5
- D. 5 : 4 Discuss
- 7. If the income of A in 2005 was Rs. 1,42,500 what was its expenditure in that year?
Options- A. Rs. 95000
- B. Rs. 95500
- C. Rs. 99,500
- D. Rs. 1,05,000 Discuss
- 8. For which course is the number of boys the minimum?
Options- A. A
- B. C
- C. E
- D. F Discuss
- 9. For Company Y, in which year is the percent of increase in percent profit over that of previous year the highest?
Options- A. 2002?03
- B. 1999?2000
- C. 2001?02
- D. Cannot be determined Discuss
- 10. What are the total marks obtained by Tanya in all the subject together?
Options- A. 402
- B. 408
- C. 412
- D. 418 Discuss
More questions
Correct Answer: $ 15,00,000
Explanation:
Correct Answer: 420
Explanation:
Correct Answer: Sliver
Explanation:
Let us assume the car which is 40% more popular than black is a and total number of car is P.
According to question,
(P x a/100 ) - (P x 5/100) = P x 5/100 x 40/100
P(a - 5)x1/100 = P x 5/100 x 40/100
(a - 5) = 5 x 40/100
(a - 5) = 200/100 = 2
a - 5 = 2
a = 2 + 5 = 7
40% more popular than Black cars = 7% popular Silver cars.
Correct Answer: 17 1 % 2
Explanation:
Correct Answer: 33.33
Explanation:
Correct Answer: 5 : 4
Explanation:
From above given graph ,
Given that :- % amount of money spent on housing = 15%
% amount of money spent on education = 12%
Required ratio = % amount of money spent on housing : % amount of money spent on education
Required ratio = 15 : 12 = 5 : 4.
Correct Answer: Rs. 95000
Explanation:
Expenditure = Income - Profit
As per given graph in question,
Income in 2005 = 1,42,500 Rs.
Profit in 2005 = 50%
Let expenditure of Company A in 2005 = Rs. E; then
E + E x 50/ 100 =142500
? E + E x 1/2 =142500
? (2E + E)/2 =142500
? 3E =142500 x 2
? E =142500 x 2/ 3
? E = 47500 x 2
? E = Rs. 95000
Correct Answer: A
Explanation:
As per first graph,
The number of students for course A = Total number of students x 20%
As per second graph,
The number of girls for course A = Total number of girls x 30%
Number of boys in course 'A' = The number of students for course A - The number of girls for course A
Number of boys in course 'A' = (1200 x 20/100 ) - ( 800 x 30/100 ) = 240 - 240 = 0
Number of boys in course 'C' = (1200 x 5/100 ) - (800 x 2/100) = 60 - 16 = 44
Number of boys in course 'E' = (1200 x 12/100 ) - 800 x 14/100 ) = 144 - 112 = 32
Number of boys in course 'F' = (1200 x 13/100 ) - ( 800 x 14/100 ) = 156 - 112 = 44
Hence, in course 'A' number of boys is minimum which is Zero.
Correct Answer: 2001?02
Explanation:
Correct Answer: 412
Explanation:
Total marks obtained by Tanya in all the subjects
= 150 x 60% + 84 + 50 x 80% + 150 x 65% + 125 x 50 + 50 x 76%
Total marks obtained by Tanya in all the subjects
= 150 x 60 /100 + 84 + 50 x 80/100 + 150 x 65/100 + 125 x 50/100 + 50 x 76/100
= 90 + 84 + 40 + 97.5 + 62.5 + 38 = 412
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