As per given bar graph , we can see that
Total production of rice in all state = (8 + 10 + 4 + 4 + 2) = 28 Lakhs tonnes
Total production of wheat in all state = (16 + 2 + 4 + 2 + 6) = 30 Lakhs tonnes
? Required ratio = Total production of Rice : Total production of Wheat
? Required ratio = 28 : 30 = 14 : 15
From above given bar graph , we can see that
The graph for rice and wheat is lowest for state D.
Hence the total production of rice and wheat in all the mentioned states is minimum in the state D.
Hence Required answer will be state D.
As per given graph we can check that which state have the Highest graph for Rice and Lowest graph for Wheat.
From above given graph ,
The production of rice in state A = 16 billion tonnes
The production of wheat in state A = 8 billion tonnes
The production of rice in state B = 10 billion tonnes
The production of wheat in state B = 2 billion tonnes
? Required Difference = The production of rice - The production of wheat
State A ? (16 ? 8) = 8 billion tonnes
State B ? (10 ? 2) = 8 billion tonnes
Hence Answer will be states A and B both .
Average pass percentage of the school = Total number of pass Boys and girls / 14
Average pass percentage of the school = (80 + 45 + 80 + 70 + 40 + 50 + 90 + 70 + 80 + 55 + 50 + 80 + 70 + 50/14 = 910)/14 = 65%
Therefore, it is clear that pass percentage of the girls in III and VI classes is less than the average pass percentage of the school.
As per graph
Average pass percentage of the boys in classes II and III = 70 + 50/2 = 120/2 = 60%
As per given graph we can find that
Average pass percentage of the boys in classes VI and Vii = 50 + 70/2 = 60%
Therefore. average pass percentage of boys in classes II and III is equal to the average pass percentage of girls in classes VI and VII.
From the given Bar graph, we can see that the Highest graph for Rice in all state will give the maximum production of Rice. The production of rice is the Highest in state B.
Hence the state B is the largest producer of rice .
i.e. State B ? 10 Lakhs tonnes
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