From above given bar graph , we can see that
The graph for rice and wheat is lowest for state D.
Hence the total production of rice and wheat in all the mentioned states is minimum in the state D.
Hence Required answer will be state D.
Required percentage = (25 + 120) x 100/536 = 100? 27
Here, miscellaneous charges for 4% = 6000
Then advertisement charges for 18% = 6000 x 18/4 = Rs. 27000
Hence, required advertisement charges = Rs. 27000
From above given graph ,
The total amount spent on football = 15 %
The total amount spent on Hockey = 15 %
Required ratio = The total amount spent on football : The total amount spent on Hockey
Required ratio = 15 : 15 = 1 : 1.
? Total boys = 45 + 186 +120 +100 + 65 + 32 + 58 + 5 = 611
? Number of boys who pass in their respective courses = 60% of 611 = 611 x 60/100 = 366.60
Total number of girls = 25 + 23 + 25 + 12 + 25 + 20 + 12 + 3 = 145
Number of girls who pass in their respective courses =70% of 145= 145 x 70/100 = 101.50
? Combined pass percent = (366.6 + 101.5) x 100/(611 + 145) = 46810/756 = 61.92 = 62%
From I : M (+) - P - T ( - )
Combining, we get M ( + ) - P - T ( - )
But II also say's J's husband has one son and two daughters.
Hence, P must be daughter of J.
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