given :- Area of the circle = 616
? ?r2 = 616
Put the value of ? = 22/7 in above equation.
we will get,
? r2 = 196
? r = 14 cm
Length of the rectangle = Diameter of the circle = 2r
Breadth of the rectangle = Radius of the circle = r
? Area of the rectangle = Length x Breadth
? Area of the rectangle = 28 × 14 = 392 cm2
from I: Two-digit marks is less than or equal to 20.
Possible marks: 10, 11, 12, 13, 14, 15, 16, 17, 18, 19 and 20
From II: Suman scored more than 9 marks.
Possible marks: 10, 11, 12, 13, 14, 15, 16, 17, 18, 19 and 20
Hence statement I and II together are not sufficient.
Let us assume the car which is 40% more popular than black is a and total number of car is P.
According to question,
(P x a/100 ) - (P x 5/100) = P x 5/100 x 40/100
P(a - 5)x1/100 = P x 5/100 x 40/100
(a - 5) = 5 x 40/100
(a - 5) = 200/100 = 2
a - 5 = 2
a = 2 + 5 = 7
40% more popular than Black cars = 7% popular Silver cars.
From above given graph ,
Given that :- % amount of money spent on housing = 15%
% amount of money spent on education = 12%
Required ratio = % amount of money spent on housing : % amount of money spent on education
Required ratio = 15 : 12 = 5 : 4.
Expenditure = Income - Profit
As per given graph in question,
Income in 2005 = 1,42,500 Rs.
Profit in 2005 = 50%
Let expenditure of Company A in 2005 = Rs. E; then
E + E x 50/ 100 =142500
? E + E x 1/2 =142500
? (2E + E)/2 =142500
? 3E =142500 x 2
? E =142500 x 2/ 3
? E = 47500 x 2
? E = Rs. 95000
As per first graph,
The number of students for course A = Total number of students x 20%
As per second graph,
The number of girls for course A = Total number of girls x 30%
Number of boys in course 'A' = The number of students for course A - The number of girls for course A
Number of boys in course 'A' = (1200 x 20/100 ) - ( 800 x 30/100 ) = 240 - 240 = 0
Number of boys in course 'C' = (1200 x 5/100 ) - (800 x 2/100) = 60 - 16 = 44
Number of boys in course 'E' = (1200 x 12/100 ) - 800 x 14/100 ) = 144 - 112 = 32
Number of boys in course 'F' = (1200 x 13/100 ) - ( 800 x 14/100 ) = 156 - 112 = 44
Hence, in course 'A' number of boys is minimum which is Zero.
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