As per second graph,
Number of girls in course 'C' = Total number of Girls x 2%
Number of girls in course 'C' = 800 x 2/100 = 16
Required difference = Number of B type tyres in 1994 - Number of B type tyres in 1995
Required difference = ( 27.5 ? 22.5 ) Million = 5 Million = 5000000.
Given :- Total population in 1988 = 146947 , increase = 11630
Total population in 1989 = Total population in 1988 + increase = 146947 + 11630 = 158577
? The number of children in 1989 = Total population in 1989 ? ( Total number of men in 1989 + Total number of women in 1989 )
= 158577 ? (70391 + 62516) = 25670.
Increase in taxation in between the financial years 2005-06 and 2006-07
= Rs. (2400 - 1730) = RS. 670 crores
Average of the total taxation during the years = total taxation for all the years / 6.
Average of the total taxation during the years = 600 + 725 + 1260 + 1730 + 2400 + 625 = 7390/6 = 1231.7 crores
Let the 7 consecutive whole numbers be (n ± 3), (n ± 2), (n ± 1), n.
Now i we consider Statement I alone
Product of these 7 integers = 702800
Since 702800 = 24 52 (251)(7), it cannot be the product of 7 consecutive whole numbers. Hence I alone is insufficient.
Now if we consider Statement II alone
Given that their sum = 105 = 7n or n = 15 and then 7 consecutive integers are 12, 13, 14, 15, 16, 17, 18 So, II alone is sufficient.
Since sum is 360 hence P + Q + R + S = 360
From statement I alone we will get P = (Q + R + S)/3 from this we can find the value of P hence statement I alone is sufficient enough.
From statement II alone we can not find the value of P.
For Delhi = | 94 + 48 + 82 + 90 + 70 | = | 384 | = 76.8. |
5 | 5 |
For H.P. = | 82 + 65 + 70 + 86 + 75 | = | 378 | = 75.6. |
5 | 5 |
For U.P. = | 78 + 85 + 48 + 70 + 80 | = | 361 | = 72.2. |
5 | 5 |
For Punjab = | 85 + 70 + 65 + 84 + 60 | = | 364 | = 72.8. |
5 | 5 |
For Haryana = | 75 + 75 + 55 + 60 + 75 | = | 340 | = 68. |
5 | 5 |
Clearly, this average is maximum for Delhi.
From I: If all of them face the centre, it means if A sits second to the left of B, then B should sit second to the right of A. But here Amit and Arun are different persons. Hence all of them do not face the centre
From II: Again suppose of them face the centre like KEN. Ali sits third to the left of ken. Now, if Amit sits on the left of Ali obviously ken should be his neighbour. But the statement says otherwise. Hence our assumption is disproved. All of them do not face the centre.
Between the financial years 2005-06 and 2006-07, maximum incresase of Rs. 670 cores had been registered in taxation.
From Statement I,
D + E = 14 x 2 = 28
From Statement II,
A + B + C + D + E + F = 4 x 50 = 200
(A + B + C + D + E + F)/6 = 28 + 200/6
= 228/6 = 38
? Statement I and II are sufficient to answer the question.
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