Average number of constructions in City R = (number of constructed building + number of demolished building + number of redeveloped building )/3
Average number of constructions in City R = 150 + 225 + 250/3 = 625/3 = 208.33 Approximate 208 %
From above given statement , we can see that
I. Perimeter of the rectangular hall = 2 ( length + breadth ) = 76 m
? 2 ( L + B ) = 76
? L+ B = 38
II. Area of the hall = 336 m2
? length x breadth = 336 m2
III. Cost of flooring per square metre = $550.
Combining (II) and (III),
Total cost = Area of the hall x Cost of flooring per square metre
= 336 × 550 = $184800.
If we look at Statement I
i = p - 17 and r = p - 103
Hence, we cannot ind how many each received so this statement is not sufficient enough.
Now by considering Statement II alone.
p + i + r = 170
Hence, we cannot find how many each received. so, this statement is not sufficient enough.
Using I sand II together, we get the value of p and the value of q and r.
From I: Saurav visited Delhi on Wednesday.
From II: He visited on Tue, wed or Thu.
In the year 2005, the number of job- seekers having their qualifications as Matriculation = 1850 - 1050 = 800
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