If in 2005 new hotels constructed were fewer by 10, what would have been the ratio between the new hotels constructed in 2004 and that constructed in 2005?

Average disbursement of loans over the years = Total disbursement of loans of all bank (In 2005 + In 2006 + In 2007 + In 2008 ) / Total number of banks
Total number of banks = Bank A + Bank B + Bank C + Bank D
Total number of banks = 1+1+1+1 = 4
Average disbursement of loans over the years = (87 + 104 + 113 +120)/4 = 424/4 = 106 ? 104
Which is nearly equal to the disbursement of loans in year 2006.

Required difference = (340 + 300 + 295 + 320 + 360) ? (350 + 225 + 185 + 200 + 240) = 1615 ? 1200 = 415.

From the level of 2004 percentage increase in export price in 2008 = (Price in 2008 - price in 2004) x 100/price in 2004
From the level of 2004 percentage increase in export price in 2008 = (500 - 150) x 100/150 = 233¹/₃%

Male children in society B = 165
Male children in society F = 69
Hence, their difference = 165 - 69 = 96

Total number of students of school T from all classes = Total number of student of (Class V + VI + VII + VIII + IX + X )
Total number of students of school T from all classes = 147 + 144 + 158 + 163 + 154 + 150 = 916
Total number of students of school S from all classes = Total number of student of ( Class V + VI + VII + VIII + IX + X )
Total number of students of school S from all classes = 159 + 142 + 149 + 140 + 140 + 142 + 168 = 900
Required percentage = 916 x 100 /900 = 101.78%

From above given table , we can see that
Since the minimum difference between the white-coloured cars sold is ( 81 - 80 ) = 1 in B type model.
Hence the correct option is E .

In society A:
Number of children = 25/100 x (250 + 350) = 1/4 x 600 = 150
Number of male children = 40/100 x 150 = 60
Number of female children = 150 - 60 = 90
In society B:
Number of children = 40/100 x (400 + 150) = 2/5 x 550 = 220
Number of male children = 75/100 x 220 = 165
Number of female children = 220 - 165 = 55
In society C:
Number of children = 16/100 x (300 + 275) = 4/25 x 575 = 92
Number of male children = 25/100 x 92 = 23
Number of female children = 92 - 23 = 69
In society D:
Number of children = 25/100 x (280 + 300) = 1/4 x 580 = 145
Number of male children = 80/100 x 145 = 116
Number of female children = 145 - 116 = 29
In society E:
Number of children = 40/100 x (180 + 250) = 2/5 x 430 = 172
Number of male children = 50/100 x 172 = 86
Number of female children = 172 - 86 = 86
In society F :
Number of children = 24/100 x (325 + 300) = 6/25 x 625 = 150
Number of male children = 46/100 x 150 = 69
Number of female children = 150 - 69 = 81
Hence, total number of female children = 90 + 55 + 69 + 29 + 86 + 81 = 410
Total Number of adult female = (350 + 150 + 275 + 300 + 250 + 300) - 410
= 1625 - 410 = 1215
Hence, required ratio = 1215 : 410 = 283 : 82

As per given table graph,
The total marks obtained by all students in Hindi = Marks obtained by ravi in Hindi + Marks obtained by riya in Hindi + Marks obtained by amit in Hindi +Marks obtained by kirti in Hindi + Marks obtained by prasad in Hindi + Marks obtained by tanya in Hindi
The total marks obtained by all students in Hindi = 50 x (84 + 86 + 88 + 90 + 86 + 80)/100 = 50 x 514/100 = 257
The average marks obtained by all students in Hindi = 257/6 = 42.83