As per given table, we can see that,
Number of students playing Basketball from all the given school
A = 200 , B = 195 , C = 245 , D = 200 , E = 225
Number of students playing Cricket from all the given school
A = 150 , B = 200 , C = 250 , D = 230 , E = 200
The total number of students playing Basketball from all the school = 200 + 195 + 245 + 200 + 225 = 1065
The total number of students playing Cricket from all the school = 150 + 200 + 250 + 230 + 200 = 1030
Required difference = The total number of students playing Basketball from all the school - The total number of students playing Cricket from all the school
Required difference = 1065 ? 1030 = 35
Total number of students for Cricket = Number of students play cricket from schools ( A + B + C + D + E )
Total number of students for Cricket = 150 + 200 + 250 + 230 + 200
Total number of students for Cricket = 1030
Number of students studying in school B in 1994 = 950 + (350 ? 150) + (225 ? 115) + (185 ? 110) + (200 ? 90) = 950 + 200 + 110 + 75 + 110 = 1445.
Required difference = (340 + 300 + 295 + 320 + 360) ? (350 + 225 + 185 + 200 + 240) = 1615 ? 1200 = 415.
As per given table, we can see that,
? Total number of players in School = sum of number of players in given all games
Total number of players in
School A = 150 + 250 + 200 + 100 + 120 = 820
School B = 200 + 125 + 195 + 130 + 180 = 830
School C = 250 + 175 + 245 + 60 + 150 = 880
School D = 230 + 100 + 200 + 40 + 130 = 700
School E = 200 + 250 + 225 + 65 + 165 = 905
Required answer will be School E .
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