Total number of students of school U from all the classes = 150 + 160 + 162 + 160 + 161 + 140 = 933
Required Percentage = 162/933 x 100 = 17.36%
Total number of students of class V from all the school = Total number of students of ( School P + School Q + School R + School S + School T + School U )
Total number of students of class V from all the school = 152 +148 + 161 + 159 + 147 + 150 = 917
Total number of students of class VI from all the school = Total number of students of ( School P + School Q + School R + School S + School T + School U )
Total number of students of class VI from all the school = 160 + 166 + 152 + 142 + 144 + 160 + = 924
Total number of students of class VII from all the school = Total number of students of ( School P + School Q + School R + School S + School T + School U )
Total number of students of class VII from all the school = 145 +150 + 140 + 149 + 158 +162 = 904
Total number of students of class VIII from all the school = Total number of students of ( School P + School Q + School R + School S + School T + School U )
Total number of students of class VIII from all the school = 156 + 155 + 145 + 140 + 163 + 160 = 919
Total number of students of class IX from all the school = Total number of students of ( School P + School Q + School R + School S + School T + School U )
Total number of students of class IX from all the school = 147 + 157 + 143 + 142 + 154 + 161 =904
Total number of students of class X from all the school = Total number of students of ( School P + School Q + School R + School S + School T + School U )
Total number of students of class X from all the school = 144 + 143 + 165 + 168 + 150 + 140 = 910
Hence, the class VI has maximum number of students.
Total number of students of school T from all classes = Total number of student of (Class V + VI + VII + VIII + IX + X )
Total number of students of school T from all classes = 147 + 144 + 158 + 163 + 154 + 150 = 916
Total number of students of school S from all classes = Total number of student of ( Class V + VI + VII + VIII + IX + X )
Total number of students of school S from all classes = 159 + 142 + 149 + 140 + 140 + 142 + 168 = 900
Required percentage = 916 x 100 /900 = 101.78%
Total number of students of class X from all school = Total number of students of class X of ( School P + School Q + School R + School S + School T + School U)
Total number of students of class X from all school = 144 + 143 + 165 + 168 + 150 + 140 = 910
Required percentage = Total number of students of class X of school P x 100/Total number of students of class X from all school
Required percentage =144 x 100/910 = 15.82 ? 16%
Male children in society B = 165
Male children in society F = 69
Hence, their difference = 165 - 69 = 96
Number of all members
= (250 + 350) + (400 + 150) + (300 + 275) + (280 + 300) + (180 + 250) + (325 + 300) + 150 + 220 + 92 + 145 + 172 + 150
= 600 + 550 + 575 + 580 + 430 + 625 + 929
= 4289
Total number of students of class IX of schools Q and R = Total number of students of class IX of (Schools Q + school R)
Total number of students of class IX of schools Q and R = 157 + 143 = 300
Total number of students of class VI of schools S and T = Total number of students of class VI of ( School S + School T)
Total number of students of class VI of schools S and T = 142 + 144 = 286
Hence, required ratio = 300 : 286 = 150 : 143
From above given table ,
Total number of students in II = 100 + 200 + 200 + 100 + 100 + 100 + 100 = 900
Total number of students in I = 200 + 300 + 500 + 100 + 400 + 300 + 200 = 2000
? Required ratio = total number of students in II : total number of students in I
Required ratio = 900 : 2000 = 9 : 20
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