What is the total number of female children staying in all the societies together?

Total number of adult males in the society A and B= (250 + 400) - (60 + 165) = 650 - 225 = 425
Total number of adult males in the society E and F = (280 + 325) - (86 + 69) = (180 + 325) - (86 + 69) = 505 - 155 = 350
Hence, required ratio = 425 : 350 = 17 : 14

In society A:
Number of children = 25/100 x (250 + 350) = 1/4 x 600 = 150
Number of male children = 40/100 x 150 = 60
Number of female children = 150 - 60 = 90
In society B:
Number of children = 40/100 x (400 + 150) = 2/5 x 550 = 220
Number of male children = 75/100 x 220 = 165
Number of female children = 220 - 165 = 55
In society C:
Number of children = 16/100 x (300 + 275) = 4/25 x 575 = 92
Number of male children = 25/100 x 92 = 23
Number of female children = 92 - 23 = 69
In society D:
Number of children = 25/100 x (280 + 300) = 1/4 x 580 = 145
Number of male children = 80/100 x 145 = 116
Number of female children = 145 - 116 = 29
In society E:
Number of children = 40/100 x (180 + 250) = 2/5 x 430 = 172
Number of male children = 50/100 x 172 = 86
Number of female children = 172 - 86 = 86
In society F :
Number of children = 24/100 x (325 + 300) = 6/25 x 625 = 150
Number of male children = 46/100 x 150 = 69
Number of female children = 150 - 69 = 81
Hence, total number of female children = 90 + 55 + 69 + 29 + 86 + 81 = 410
Total Number of adult female = (350 + 150 + 275 + 300 + 250 + 300) - 410
= 1625 - 410 = 1215
Hence, required ratio = 1215 : 410 = 283 : 82

Percentage of girls in Business Management course = (25 + 25) x 100/160 = 31.25
Percentage of girls in typewriting course = (23 + 20) x 100/261 = 16.47
Percentage of girls in stenography course = (25 + 12) x 100/215 =12.56
And percentage of girls in typewriting and stenography course = (12 + 3) x 100/120 = 12.50
Hence, it is clear from the above that percentage of girls in Business Management course is the highest,

? Number of students in Business Management course = 160
Number of students in typewriting corse = 261
Number of students in stenography corse = 215
? Requied percent = (160 + 215 - 261/261) x 100 ? 44%

Required percentage = (25 + 120) x 100/536 = 100? 27

Number of all members
= (250 + 350) + (400 + 150) + (300 + 275) + (280 + 300) + (180 + 250) + (325 + 300) + 150 + 220 + 92 + 145 + 172 + 150
= 600 + 550 + 575 + 580 + 430 + 625 + 929
= 4289

Male children in society B = 165
Male children in society F = 69
Hence, their difference = 165 - 69 = 96

Total number of students of class X from all school = Total number of students of class X of ( School P + School Q + School R + School S + School T + School U)
Total number of students of class X from all school = 144 + 143 + 165 + 168 + 150 + 140 = 910
Required percentage = Total number of students of class X of school P x 100/Total number of students of class X from all school
Required percentage =144 x 100/910 = 15.82 ? 16%

Total number of students of school T from all classes = Total number of student of (Class V + VI + VII + VIII + IX + X )
Total number of students of school T from all classes = 147 + 144 + 158 + 163 + 154 + 150 = 916
Total number of students of school S from all classes = Total number of student of ( Class V + VI + VII + VIII + IX + X )
Total number of students of school S from all classes = 159 + 142 + 149 + 140 + 140 + 142 + 168 = 900
Required percentage = 916 x 100 /900 = 101.78%

Total number of students of class V from all the school = Total number of students of ( School P + School Q + School R + School S + School T + School U )
Total number of students of class V from all the school = 152 +148 + 161 + 159 + 147 + 150 = 917
Total number of students of class VI from all the school = Total number of students of ( School P + School Q + School R + School S + School T + School U )
Total number of students of class VI from all the school = 160 + 166 + 152 + 142 + 144 + 160 + = 924
Total number of students of class VII from all the school = Total number of students of ( School P + School Q + School R + School S + School T + School U )
Total number of students of class VII from all the school = 145 +150 + 140 + 149 + 158 +162 = 904
Total number of students of class VIII from all the school = Total number of students of ( School P + School Q + School R + School S + School T + School U )
Total number of students of class VIII from all the school = 156 + 155 + 145 + 140 + 163 + 160 = 919
Total number of students of class IX from all the school = Total number of students of ( School P + School Q + School R + School S + School T + School U )
Total number of students of class IX from all the school = 147 + 157 + 143 + 142 + 154 + 161 =904
Total number of students of class X from all the school = Total number of students of ( School P + School Q + School R + School S + School T + School U )
Total number of students of class X from all the school = 144 + 143 + 165 + 168 + 150 + 140 = 910
Hence, the class VI has maximum number of students.