What is the respective ratio of the number of the adult females to the total number of female children staying in all the societies together?

In society A:
Number of children = 25/100 x (250 + 350) = 1/4 x 600 = 150
Number of male children = 40/100 x 150 = 60
Number of female children = 150 - 60 = 90
In society B:
Number of children = 40/100 x (400 + 150) = 2/5 x 550 = 220
Number of male children = 75/100 x 220 = 165
Number of female children = 220 - 165 = 55
In society C:
Number of children = 16/100 x (300 + 275) = 4/25 x 575 = 92
Number of male children = 25/100 x 92 = 23
Number of female children = 92 - 23 = 69
In society D:
Number of children = 25/100 x (280 + 300) = 1/4 x 580 = 145
Number of male children = 80/100 x 145 = 116
Number of female children = 145 - 116 = 29
In society E:
Number of children = 40/100 x (180 + 250) = 2/5 x 430 = 172
Number of male children = 50/100 x 172 = 86
Number of female children = 172 - 86 = 86
In society F :
Number of children = 24/100 x (325 + 300) = 6/25 x 625 = 150
Number of male children = 46/100 x 150 = 69
Number of female children = 150 - 69 = 81
Hence, total number of female children = 90 + 55 + 69 + 29 + 86 + 81 = 410
Total Number of adult female = (350 + 150 + 275 + 300 + 250 + 300) - 410
= 1625 - 410 = 1215
Hence, required ratio = 1215 : 410 = 283 : 82