As we know the formula,
Profit = Sales - Expenses
Solve option one by one.
Option (A) in year 1998
Profit in year 1998 = Sales in 1998 - Expenses in 1998
Profit in year 1998 = 800 - 700 = 100
Capital in year 1998 = 200 (As per given graph)
Ratio of profit to capital in year = 100 / 200 = 0.5
Similarly Option (B) in year 1995
Profit in year 1995 = Sales in 1995 - Expenses in 1995
Profit in year 1995 = 500 - 400 = 100
Capital in year 1995 = 100 (As per given graph)
Ratio of profit to capital in year = 100 / 100 = 1
Similarly Option (C) in year 1996
Loss in year 1996 = Sales in 1996 - Expenses in 1996
Loss in year 1996 = 500 - 400 = 100
Profit in year 1996 = 500 - 400 = - 100
Capital in year 1996 = 100 (As per given graph)
Ratio of profit to capital in year = - 100 / 100 = -1
Similarly Option (D) in year 1997
Loss in year 1997 = Sales in 1997 - Expenses in 1997
Loss in year 1997 = 600 - 400 = 200
Profit in year 1997 = 600 - 400 = - 200
Capital in year 1997 = 200 (As per given graph)
Ratio of profit to capital in year 1997 = Profit / Capital
Ratio of profit to capital in year 1997 = - 200 / 200 = -1
As we can see the year 1995 has the highest ratio for Profit to capital.
Difference in Required number = Number of Pep-up drink sold in 1990 - Number of Cool-sip drink sold in 1990.
Difference in Required number = 30 million ? 20 million = 10 million.
Difference in Required number = 10 million = 10 x 1000000 ( Since 1 million = 1000000 )
Difference in Required number = 10 million = 10000000
By comparing the Sale of Pep-up for all years and we found that the Sale of Pep-up was the maximum in the year 1989.
Top two highest run scorer are A and E as per given graph.
Total match = 20
Total match played by A if matches having 0's were ignored = 19
Total match played by E if matches having 0's were ignored = 20
Runs Scored by A = 994
Runs Scored by E = 772
Average runs of A = 994 / 19 = 52.3
Average runs of E = 772 / 20 = 38.6
Difference = 52.3 ? 38.6 = 13.7
From above table ,
Number of blue-colour cars of model 'C' sold in Metro M = 50000
Number of red colour cars of model 'F' sold in Metro H = 34000
Required difference = Number of blue-colour cars of model 'C' sold in Metro M ? Number of red colour cars of model 'F' sold in Metro H
= ( 50000 ? 34000 )= 16000.
From the values given in above table , it is clear that during the period 1989?94 , the production of S's car is continuous increase . Hence answer will be S type of cars .
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