The available digits are 0, 1, 2,...., 9. The first digit can be chosen in 9 ways (0 not acceptable), the second digit can be accepted in 9 ways (digit repetition not allowed). Thus, the code can be made in 9 x 9 = 81 ways.
Now, there are only 4 digits which can create confusion 1, 6, 8, 9. The same can be given in the following ways
Total number of ways confusion can arise
= 4 x 3 = 12
Thus, the ways in which no such confusion arise = 81-12 =69
Required probability = favorable number of cases/ total number of
=8P5 / 8 5 = 105/512
Let the original price be 100 Rs.
So reduced price = 100 X 0.95 X 0.90 X 0.80 = 68.40
? Single discount = (100 ? 68.4) % = 31.6%
6.66% of MP = 25
? MP = 375
? SP = MP - 25 = 350
According to given question , we have
?. x3 - 371 = 629
? x = ?1000 = 10
?. y3 - 543 = 788
? y = ?1331 = 11
From above both equations it is clear that x < y is correct answer .
Number are 13, 23, 33, 43, 53, 63.
So, the missing number is 73 = 343.
Let the length of rectangle = L m
? Breadth of rectangle = B m
Using conditions from the question,
L - B = 23 ....(i)
2(L + B) = 206
L + B = 103 ....(ii)
On adding Eqs. (i) and (ii), we get
2L = 126
? L = 63 m
? B = 103 - 63 = 40 m
Then , area of rectangle = L x B
= 63 x 40
= 2520 m2 .
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