Total balls in the box = 5
Second red ball can be drawn in two ways
Case I. First ball is white and second ball is red.
Its probability = 3/5.2/4 = 6/20 = 3/10
Case II: First ball is red and second ball is red
Its probability = 2/5.1/4 = 2/20 = 1/10
Hence, reqd. probability
= 3/10 + 1/10 = 4/10 = 2/5
You can have
W, W, B or W, B, W or B, W, W
Reqd. probability
= 3/4. 2/4. 3/4 + 3/4. 2/4. 1/4 + 1/4. 2/4. 1/4
= 9/32 + 3/32 + 1/32 = 13/32
There are 13 hearts and 3 more kings
? P(heart or a king) = (13 + 3)/52 = 4/13
? P (neither a heart nor a king) = 1 - 4/13 = 9/13
n(S) = Number of ways of drawing 2 cards out of 52
52C2 = (52 x 51) / (2 x 1) = 1326
n(E) = Number of ways of drawing 2 cards out of 4
= 4C2 = (4 x 3)/2 = 6
? P(E) = 6/1326 = 1/221
Total number of outcomes = 10c4 = 210
Favourable number of outcomes = 3c2 x 2c2 = 3 x 1 = 3
? Required probability = 3/210 = 1/70
Total Number of outcomes = 10C3 = 120
Number of outcomes not containing red balls = 5C3 = 10
? Probability that at least one is red = 1 - 10/120 = 11/12
Total number of ways
= n(s) = 6c2 = 15
Favorable number of ways
= n(E) = 3C1 x 3C1= 9
? Required probability = 9/15 = 3/5
Required probability = P(A) x P(B)
= (1 - 1/4) x (1 - 1/3) = 3/4 x 2/3 = 1/2
Total lottery tickets = 10000
Total prize in the lottery = 10
? Probability getting a prize
= 10/10000 = 1/1000
Now, probability of not getting a prize
= 1 - probability of getting a prize
= 1 - (1/1000)
= 999/1000
Required probability = P (A) x p (B)
= (1- 1/4) x (1- 1/6) = (3/4) x (5/6)
= 5/8
Total ways = 13c2
Favourable number ways of selecting men only = 8c2
? Probability of selecting no woman
= 8c2 / 13c2
= 14/39
? Probability of selecting at least one woman
= 1 - (14 / 39)
= 25 / 39
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