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- Question
- What is the probability that a number selected from the numbers 1, 2, 3, 4, 5....16 is a prime number?
Options- A. 1/16
- B. 5/8
- C. 3/8
- D. 7/16
- Correct Answer
- 3/8
ExplanationS = {1, 2, 3, ......16}
E = {2, 3, 5, 7, 11, 13}
? P(E) = n(E)/n(S) = 6/16= 3/8 - 1. What rate per cent per annum compound interest will Rs. 3,000 in 3 years if the interest is reckoned half yearly?
Options- A. 12%
- B. 13%
- C. 14%
- D. 15% Discuss
- 2. The population of a town at the beginning of the year 1986 was 2,65,000. If the rate of increase be 52 per thousand of the population. Find the population at the beginning of the year 1991.?
Options- A. 3,40,400
- B. 3,41,400
- C. 3,42,400
- D. 3,43,400 Discuss
- 3. The number of digits in the numeral for (875) 16?
Options- A. 47 digit
- B. 48 digit
- C. 49 digit
- D. 50 digit Discuss
- 4. The value of 1/(log 2 ?) + 1/(log 6 ?) is?
Options- A. greater then 1
- B. less than 1
- C. between 5 and 6
- D. None of these Discuss
- 5. Given log 10 2 = 0.30103, log 10 3 = 0.47712. Find the number of digit, in 3 12 x 2 8?
Options- A. 6
- B. 7
- C. 8
- D. 9 Discuss
- 6. An urn contains 9 red, 7 white and 4 black balls. A ball is drawn at random. What is the probability that the ball drawn is not red?
Options- A. 1/11
- B. 9/20
- C. 2/11
- D. 11/20 Discuss
- 7. In a lottery there are 20 prizes and 15 blanks. What is the probability of getting prize?
Options- A. 1/10
- B. 2/5
- C. 4/7
- D. 2/7 Discuss
- 8. The odds in favour of an event are 3 : 5. The probability of occurrence of the event is?
Options- A. 3/5
- B. 3/8
- C. 1/3
- D. 1/5 Discuss
- 9. The probability of getting heads in both trials when a balanced coin is tossed twice will be?
Options- A. 1/4
- B. 1/2
- C. 1
- D. 3/4 Discuss
- 10. A number is chosen at random among the first 120 natural numbers. The probability of the number chosen being a multiple of 5 or 15 is?
Options- A. 1/5
- B. 1/8
- C. 1/6
- D. None of these Discuss
Probability problems
Search Results
Correct Answer: 14%
Explanation:
? 3000 = 2000(1 + r/200)6
? 3/2 = (1 + r/200)6
? 1 + r/200 = (3/2)1/6
? log(1 + r/200)= 1/6(log 3 - log 2 )
? log(1 + r/200)= 1/6(0.4771-.3010)
= 0.02935
? (1 + r/200) = antilog(.02935)
? 1 + r/200 = 1.070 = 1 + 7/100
? r = 14%
Correct Answer: 3,41,400
Explanation:
We have r = Rate of increase
= 52/1000 x 100
= 5.2, n = 5, P0 = 265000
? P = 265000(1 + 5.2 / 100)5
? log P = log 265000 + 5(log 105.2 - log 100)
= 5.4232 + 5(2.0220 - 2)
= 5.4232 + 0.1100
= 5.5332
? P = antilog(5.5332) = 341400
Correct Answer: 48 digit
Explanation:
? N = (875)16
? log N = log (875)16
? log N = 16 log (875)
= 16 x (2.942)
= 47.072
? No.of digits = 47 + 1 = 48
Correct Answer: greater then 1
Explanation:
Given exp. = 1/(log2 ?) + 1/(log6 ?)
= log? 2 + log? 6
= log? (2 x 6)
= log?12
Since 12 > ? so the value of given expression is more than 1.
Correct Answer: 9
Explanation:
Let N = 312 x 28
? log N = 12 x log3 + 8 x log 2
? log N = 12 x 0.47712 + 8 x 0.30103
? log N = 8.13368
? No.of digits = 8 + 1 = 9
Correct Answer: 11/20
Explanation:
P (red) = 9 / (9 + 7 + 4) = 9/20
? P(not-red) = (1 - 9/20) = 11/20
Correct Answer: 4/7
Explanation:
P (getting a prize ) = 20 / (20 + 15 ) = 20 / 35 = 4/7
Correct Answer: 3/8
Explanation:
Number of cases favourable of E = 3
Total Number of cases = (3 + 5 ) = 8
? P(E) = 3/8
Correct Answer: 1/4
Explanation:
Probability of getting head in one trail = 1/2
? Reqd Probability of getting heads in both the trails = 1/2 x 1/2 = 1/4
Correct Answer: 1/5
Explanation:
? Total no. of favourable cases i,e., (5, 10, 15, 20, 25, 30, ....., 105, 110, 115, 120) = 24.
? Reqd . Prob = 24/120 = 1/5
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