? 3000 = 2000(1 + r/200)6
? 3/2 = (1 + r/200)6
? 1 + r/200 = (3/2)1/6
? log(1 + r/200)= 1/6(log 3 - log 2 )
? log(1 + r/200)= 1/6(0.4771-.3010)
= 0.02935
? (1 + r/200) = antilog(.02935)
? 1 + r/200 = 1.070 = 1 + 7/100
? r = 14%
We have r = Rate of increase
= 52/1000 x 100
= 5.2, n = 5, P0 = 265000
? P = 265000(1 + 5.2 / 100)5
? log P = log 265000 + 5(log 105.2 - log 100)
= 5.4232 + 5(2.0220 - 2)
= 5.4232 + 0.1100
= 5.5332
? P = antilog(5.5332) = 341400
? N = (875)16
? log N = log (875)16
? log N = 16 log (875)
= 16 x (2.942)
= 47.072
? No.of digits = 47 + 1 = 48
Given exp. = 1/(log2 ?) + 1/(log6 ?)
= log? 2 + log? 6
= log? (2 x 6)
= log?12
Since 12 > ? so the value of given expression is more than 1.
Let N = 312 x 28
? log N = 12 x log3 + 8 x log 2
? log N = 12 x 0.47712 + 8 x 0.30103
? log N = 8.13368
? No.of digits = 8 + 1 = 9
? x = 264
? log x = log 264
? log x = 64 log 2
= 64 x .3010 = 19.264
? No.of digits = 19 + 1 = 20
S = {1, 2, 3, ......16}
E = {2, 3, 5, 7, 11, 13}
? P(E) = n(E)/n(S) = 6/16= 3/8
P (red) = 9 / (9 + 7 + 4) = 9/20
? P(not-red) = (1 - 9/20) = 11/20
P (getting a prize ) = 20 / (20 + 15 ) = 20 / 35 = 4/7
Number of cases favourable of E = 3
Total Number of cases = (3 + 5 ) = 8
? P(E) = 3/8
Probability of getting head in one trail = 1/2
? Reqd Probability of getting heads in both the trails = 1/2 x 1/2 = 1/4
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