Given log( x - 5) = log(x) - log(5)
? x -5 = x/5
? x = 25/ 4 ....(i)
Again from question
log(y - 6) = log(y) - log(6)
? y - 6 = y/6
? y = 36/5 ...(ii)
From equations (i) & (ii) x < y
857 = (23)57 = 2171
? Required answer = (171 log10 2 + 1 )
= [171 x 0.3010] + 1 = [51.4710] +1
= 51+1 =52
810 = (23)10
? Required answer = [30 log10 2 + 1]
= [30 x 0.3010] + 1
= 9.03 + 1
= 9 + 1
= 10
A = log27625 + 7log1113
= log3354 + 7 log1113
= 4/3 log3 5 + 7 log1113
B = log9125 + 13 log117 = log32 53 + 13 log117
= 3/2 log3 5 +13 log11 7
Let log3 5 = x and by the above rule
7 log11 13 = 13 log11 7
Therefore, A = 4/3 x + 13 log11 7
and B = 3/2 x + 13 log11 17
clearly, A < B hence (B) is the correct answer.
logan / logabn = [( log n / log a) / (log n / log (a.b))]
= log (a.b) / log a
= ( log a + log b) / log a
= 1 + (log b / log a)
= 1 + logab
? 10x = 1730/1000
? log10x= log101730 - log101000
? x = 3.2380 - 3
= 0.2380
Given log (x + 4) = log(4) + log(x)
? x + 4 = 4x
? x = 4/3
Similarly y = 5/4
? x > y
? ax = b
? loga b = x
? by = c
? logb c = y
? cz = a
? logc a = z
? xyz = logab x logbc x logca = 1
logxy =100, log2x = 10
? log y / log x = 100 and log x / log 2 = 10
? log y / log 2 = 100 x 10 = 1000
? log2y = 1000
? y = 21000
logx4 = log 4 / log x = 2/5
? 2log2 / log x = 2/5
? log x =5log 2 = log 25
? log x = log 32
? x = 32
? log1227 = a
? log 27 / log 12 = a
? a log 12 = log 33
? a log ( 3 x 4 ) = 3 log 3
? a[log 3 + log 4] = 3 log 3
? a log 4 + a log 3 = 3 log 3
? a log 22 = ( 3 - a) log 3
? 2a log 2 = (3 - a) log 3
? log 2 / log 3 = (3 - a) / 2a
Now log616 = log16 / log 6 = log 24 / log (2 x 3) = 4 log 2 / ( log 2 + log 3)
= [4 (log 2 / log 3)] / [(log 2 / log 3) + 1]
= 4[(3 - a) / 2a] / [{(3 - a) / 2a } + 1]
= 4(3 - a) / (3 + a)
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