Given Exp. = log927 - log279
= log27 / log9 - log9 / log27
= 3log3 / 2log3 - 2log3 / 3log3
= 3/2 - 2/3 = 5/6
(log53) x log3 54 = [log3 / log5] x 4 x [log5 / log3]
= 4
If log 125 / log 5 = x
then x = 3log5 / log5= 3
log10(103.10x) = log10 103 + log10(10x)
= 3 + 2.7532
= 5.7532
log105 = log10(10/2)
= log1010 - log102
= 1-0.3010
= 0.6990
? px = q
? logppx = logpq
? xlogpp = logpq
? x = logpq (?logpp = 1)
? 10x = 1730/1000
? log10x= log101730 - log101000
? x = 3.2380 - 3
= 0.2380
logan / logabn = [( log n / log a) / (log n / log (a.b))]
= log (a.b) / log a
= ( log a + log b) / log a
= 1 + (log b / log a)
= 1 + logab
A = log27625 + 7log1113
= log3354 + 7 log1113
= 4/3 log3 5 + 7 log1113
B = log9125 + 13 log117 = log32 53 + 13 log117
= 3/2 log3 5 +13 log11 7
Let log3 5 = x and by the above rule
7 log11 13 = 13 log11 7
Therefore, A = 4/3 x + 13 log11 7
and B = 3/2 x + 13 log11 17
clearly, A < B hence (B) is the correct answer.
810 = (23)10
? Required answer = [30 log10 2 + 1]
= [30 x 0.3010] + 1
= 9.03 + 1
= 9 + 1
= 10
857 = (23)57 = 2171
? Required answer = (171 log10 2 + 1 )
= [171 x 0.3010] + 1 = [51.4710] +1
= 51+1 =52
Comments
There are no comments.Copyright ©CuriousTab. All rights reserved.