Volume of the cuboid = 9 x 8 x 6 = 432 cm3
Volume of the cube = 1/2 x 432 = 216 cm3
? Each side of cube = ?216 = 6 cm
Total surface area of the cube = 6 x (Side)2 = 6 x 62
= 6 x 36 = 216 sq cm
Given, 4?r2 = 2?rh
? h = 2r
Now, required ratio
= 4/3?r3 : ?r2h
= 4r : 3h
= 4r : 6r [ ? h = 2r]
= 2 : 3
Let r = Radius of cylinder = Radius of sphere, h = Height of the cylinder.
According to the question.
4/3?r3 = ?r2h
? h = 4r/3
? 4r = 3h
? 2r = 3/2h
? 2r/h = 3/2
? Required ration = 3 : 2
Volume of 1 bullet = 4/3?(2)3 = (32/3 x 22/7) cm3
Volume of the cube = (44)3
? Number of bullets = Volume of solid/Volume of 1 bullet
= (44)3 x 3 x 7 / 32 x 22 = 2541
Let required number of coins be n, Then,
n x 1/3 x ? (1/10)2 x 1 = ? x (3)2 x 5
? n = 9 x 5 x 3 x 100 = 13500
Ratio of curved surface area of cylinder and cone = [2?rh] / [?r?h2 + r2]
= [2 x 6 x 8] / [6 x ?62 + 82]
= 96/(6 x 10) = 96/60 = 8/5 = 8 : 5
Given, l = Length of the cuboid = 5 x 7 = 35 cm
h = Breadth of the cuboid = 5 cm
h = Height of the cuboid = 5 cm
? Surface area = 2(lb + bh + lh) = 2[35 x 5 + 5 x 5 + 35 x 5]
= 2[175 + 25 + 175]
= 2 x 375 = 750 sq cm
1 hec = 10000 m3
Volume of water = Base area x Height
= (10000 x 10)/100 = 1000 m3
Given, radius of pipe 5/2 x 10 = 5/20 cm [? 1 cm = 10 mm]
Height of pipe = 1000 cm
Radius of vessel = 20 cm and height = 24 cm
Volume of water flow in one minute from cylindrical pipe = ? (5/20)2 x 1000
= 125/2 ? cm3
and volume of conical vessel = 1/3 ?(20)2 x 24 = 3200? cm3
? Required time = (3200? x 2) / 125?
= 511/5 or 51 min 12 s
Let level of water will be increased by h cm
? x (15)2 x h = (4/3)?(10)3
? h = [(4/3) x 10 x 10 x 10] / [15 x 15]
= 525/27 cm
Volume of water = Volume of conical flask = (1/3)?r2h
Now, the water is poured into cylindrical flask.
? Volume of cylinder = Volumes of water
? ? (mr)2 x Height = (1/3)?r2h
? Height = h/3m2
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