Surface area = 6a2 = 726
? a2 = 121
? a = 11 cm
? Volume of the cube = (11 x 11 x 11) cm3
= 1331 cm3
? a3 = 512 = 8 x 8 x 8
? a = 8 cm
? Surface area = 6a2
=[6 x (8)2] cm2
=384 cm2
Let one diagonal be k.
Then, other diagonal = (60k/100) = 3k/5 cm
Area of rhombus =(1/2) x k x (3k/5) = (3/10)
= 3/10 (square of longer diagonal)
Hence, area of rhombus is 3/10 times.
Area of square plate = (Side)2
= (2d)2
= 4d2
Area of circular plate = ? (d/2)2
= ?d2/4
? Number of square plates
= [(4d2)/4] / [(?d2)/4]
= (4 x 4)/?
? 5
Since, nearest integer value is 5.
Area of square = (Side)2 = 202
= 400 sq cm
? Area of rectangle
= 1.8 x 400 = 720 sq cm
Let length and breadth of rectangle be 5k and k respectively.
Then, according to the question,
5k x k = 720
? 5k2 = 720
? k2 = 720/5 = 144
? k = ?144 = 12 cm
Perimeter of rectangle = 2(5k + k) = 12k
= 12 x12 = 144 cm
Given that, l = 2b [Here l = length and b = breadth]
Decrease in length = Half of the 10 cm = 10/2 = 5 cm
Increase in breadth = Half of the 10 cm = 10/2 = 5 cm
Increase in the area = (70 + 5) = 75 sq cm
According to the question,
(l - 5) (b + 5) = lb + 75
? (2b - 5) (b + 5) = 2b2 + 75 [since l = 2b]
? 5b - 25 = 75
? 5b = 100
? b = 100/ 5 = 20
? l = 2b = 2 x 20 = 40 cm
Let the edge of original cube = x cm
Edge of new cube = (2x) cm
Ratio of their volumes = x3 : (2x)3
= x3 : 8x3
= 1 :8
Thus the volumes be comes 8 times.
Volume of new cube = (5)3 + (4)3 + (3)3 cm3
= 126 cm3
Edge of this cube = (6 x 6 x 6)1/3 = 6 cm
Volume of new cube = [(5)3 + (4)3 + (3)3] cm3
= 216 cm3
Edge of this cube = ( 6 x 6 x 6)1/3 = 6 cm
Since, the box is in the form of a cuboid.
? Required length = ?102 +82 + 52 cm
= ?189
= ?9 x 21
= 3?21 cm
Maximum number of pieces that can be cut out
= (Volume of cake) / (Volume of Each piece of cake)
= (5 x 30 x 30)/(5 x 5 x 10) = 18
Comments
There are no comments.Copyright ©CuriousTab. All rights reserved.