Discussion
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- Question
- The length of each side of an equilateral triangle having an area of 4?3 cm 2 is?
Options- A. 4/?3 cm
- B. ?3/4 cm
- C. 3 cm
- D. 4 cm
- Correct Answer
- 4 cm
ExplanationArea of equilateral triangle = ?3/4 a2 = 4?3.
? a2 = 16
? a = 4 cm - 1. The ratio of the area of square of side a and equilateral triangle of side a is?
Options- A. 2 :1
- B. 2 : ?3
- C. 4 :3
- D. 4 : ?3 Discuss
- 2. If the diameters of a circle is increased by 100% . Its area is increased by?
Options- A. 100%
- B. 200%
- C. 300%
- D. 400% Discuss
- 3. The ratio of the area of two square, one having and double its diagonal than the other is?
Options- A. 2:1
- B. 3:1
- C. 3:2
- D. 4:1 Discuss
- 4. A park of 10 meters long and 8 meters broad. What is the length of the longest pole that can be placed in the park?
Options- A. 10 metres
- B. 12.8 metres
- C. 13.4 metres
- D. 18 metres Discuss
- 5. The length of a rectangle is twice its breadth. If its length is decreased by 5 cm and the breadth is increased by 5 cm, the area of the rectangle is increased by 75 cm 2 . Therefore , the length of the rectangle is?
Options- A. 20 cm
- B. 30 cm
- C. 40 cm
- D. 50 cm Discuss
- 6. The area of an equilateral triangle whose side is 8 cms is?
Options- A. 64 cm2
- B. 16?3 cm2
- C. 21.3 cm2
- D. 4?3 cm2 Discuss
- 7. Find the area of a triangle whose sides measure 8 cm, 10 cm and 12 cm.
Options- A. 8?63 sq cm
- B. 5?63 sq cm
- C. 6?53 sq cm
- D. 7?93 sq cm Discuss
- 8. Find the perimeter of a triangle with sides equal to 6 cm, 4 cm and 5 cm.
Options- A. 14 cm
- B. 18 cm
- C. 20 cm
- D. 15 cm Discuss
- 9. The area of a right angled triangle is 40 sq cm. If its base is equal to 28 cm. find its height.
Options- A. 36/7 cm
- B. 46/7 cm
- C. 26/7 cm
- D. 56/7 cm Discuss
- 10. The area of a right angled triangle is 10 sq cm. If its perpendicular is equal to 20 cm, find its base.
Options- A. 1 cm
- B. 4 cm
- C. 3 cm
- D. 2 cm Discuss
Area problems
Search Results
Correct Answer: 4 :3
Explanation:
Ratio of area = a2/ ?(3/4) a2
= 4/?3 = 4:?3
Correct Answer: 300%
Explanation:
Original area = ?(d/2)2
= (?d2) / 4
New area = ?(2d/2)2
= ?d2
Increase in area = (?d2 - ?d2/4)
= 3?d2/4
? Required increase percent
= [(3?d2)/4 x 4/(?d2) x 100]%
= 300%
Correct Answer: 4:1
Explanation:
Let the diagonal of one square be (2d) cm
Then, diagonal of another square = d cm
? Area of first square = [ 1/2 x (2d)2] cm2
Area of second square = (1/2 x d2) cm2
? Ratio of area = (2d)2/ d2
= 4/1 = 4: 1
Correct Answer: 12.8 metres
Explanation:
Length of the longest pole = ? [(10)2 + (8)2] m
= ? 164 m
= 12.8 m
Correct Answer: 40 cm
Explanation:
Let breadth = b, length = 2b
? Area of rectangle = 2b x b
= 2b2
As per question.
? (2b - 5 ) (b + 5 ) = 2b2 + 75
? 5b = 75 + 25
? 5b = 100
? b = 100 / 5 = 20
Hence, length of the rectangle =2b
= 2 x 20
= 40 cm.
Correct Answer: 16?3 cm2
Explanation:
Req. Area = ?3/4 x a2 = ?3/4 x 82 cm2
= 16?3 cm2
Correct Answer: 5?63 sq cm
Explanation:
Given that, a = 8 cm, b = 10 cm and c = 12 cm
We know, that
s = (a + b + c)/2
= (8 + 10 + 12)/2
= 30/2 = 15 cm
? (s - a) = (15 - 8) = 7 cm
(s - b) = (15 - 10) = 5 cm
(s - c) = (15 - 12) = 3 cm
? Area = ?s(s - a) (s - b) (s - c)
= ?15 x 7 x 5 x 3
= ?1575
= ?25 x 63
= 5?63 cm
Correct Answer: 15 cm
Explanation:
Given that, a = 6 cm, b = 4 cm and c = 5 cm
Required perimeter = a + b + c
= 6 + 4 + 5 cm
= 15 cm
Correct Answer: 26/7 cm
Explanation:
Given that,
area = 40 sq cm,
base = 28 cm and
height = perpendicular = ?
Area = (base x perpendicular) / 2
? 40 = (28 x perpendicular) / 2
? perpendicular = 40/14 = 20/7
= 26/7 cm
Correct Answer: 1 cm
Explanation:
Given that, area = 10 sq cm,
perpendicular = 20 cm and base = ?
area = (base x Perpendicular) / 2
? 10 = (base x 20) / 2
? base = 1 cm
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