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- Question
- What will be the present worth of ? 169 due in 2 yr at 4 % pa compound interest?
Options- A. ? 156.25
- B. ? 160
- C. ? 150.50
- D. ? 154.75
- Correct Answer
- ? 156.25
ExplanationGiven R = 4 %, n = 2 yr and A = ? 169.
P = ?
Amount = P(1 + R/100)n
? 169 = P(1 + 4/100 )2
? 169 = P(26/25)2
? P = 169 x (25 x 25)/(26 x 26)
? P = 105625 / 676
= ? 156.25 - 1. A sum amounts to ? 1352 in 2 yr at 4% compound interest. The sum is
Options- A. ? 1250
- B. ? 1200
- C. ? 1300
- D. ? 1260 Discuss
- 2. What will be the compound interest on a sum of ? 50000 after 3 yr at the rate of 12% pa?
Options- A. ? 80000
- B. ? 70246.40
- C. ? 20246.40
- D. ? 70000 Discuss
- 3. Rohit earns an interest of ? 1656 for the third year and ? 1440 for the second year on the same sum. Find the rate of interest if it is lent at compound interest?
Options- A. 18%
- B. 12%
- C. 15%
- D. None of these Discuss
- 4. A sum of ? 2400 deposited at CI, Double after 5 yr. After 20 yr it will become?
Options- A. ? 24000
- B. ? 38400
- C. ? 19200
- D. Cannot be determined Discuss
- 5. At what rate of compound interest per annum will a sum of Rs. 1200 become Rs. 1348.32 in 2 years?
Options- A. 7%
- B. 7.5%
- C. 6%
- D. 6.5% Discuss
- 6. Find the compound interest on ? 31250 at 16 % pa compounded quaterly for 9 months.
Options- A. ? 4000
- B. ? 3902
- C. ? 3500
- D. ? 4200 Discuss
- 7. A sum amounts to ? 2916 in 2 yr and ? 3149.28 in 3 yr at compound interest. The sum is?
Options- A. ? 1500
- B. ? 2500
- C. ? 2000
- D. ? 3000 Discuss
- 8. The difference between the compound interest and the simple interest on a certain sum at 5% per annum for 2 years is Rs. 1.50. The sum is?
Options- A. Rs. 600
- B. Rs. 500
- C. Rs. 400
- D. Rs. 300 Discuss
- 9. The simple interest on a certain sum for 2 years at 10% per annum is Rs.90. The corresponding compound interest is?
Options- A. Rs. 99
- B. Rs. 95.60
- C. Rs. 94.50
- D. Rs. 108 Discuss
- 10. What is the principle amount which earns Rs. 132 as compound interest for the second years at 10% per annum?
Options- A. Rs. 1000
- B. Rs. 1200
- C. Rs. 1320
- D. None of these Discuss
Compound Interest problems
Search Results
Correct Answer: ? 1250
Explanation:
Using the formula, A = p ( 1 + R/100 )n
? 1352 = p(1 + 4/100 )2
? 1352 = p(1.04 )2
? p = 1352/(1.04)2 = ? 1250
Correct Answer: ? 20246.40
Explanation:
Given, P = ? 50000, R = 12% and n = 3 Yr
According to the formula,
Amount = P (1 + R/100 )n
= 50000 (1 + 12/100 )3
= 50000 x (28/25) x (28/25) x (28/25)
= 16 x (28 x 28 x 28)/ 5 = 351232/5
= ? 70246.40
? CI = 702446.40 - 50000 = ? 20246.40
Correct Answer: 15%
Explanation:
Interest on ? 1440 = ? 216 for the third year
? Rate percentage = (216 x 100)/(1440 x 1) = 15 %
Correct Answer: ? 38400
Explanation:
2P = P (1 + R/100) 5
? 24 P = P(1 + R/100)20
? The amount becomes 24 times
= 16 times and required amount = 2400 x 16 = ? 38400
Correct Answer: 6%
Explanation:
Let the rate be R% per annum.
Then,
1200 x (1 + R/100)2 = 1348.32
? (1 + R/100)2 =1348.32/1200 = 1.1236 = (1.06)2
? (1 + R/100) =1.06
? R/100 = 0.06
? R = 6%
Correct Answer: ? 3902
Explanation:
Given, P = ? 31250,
n = 9 Month = 3 quarters and
R = 16% pa = 4% per quarter
According to the formula
Amount = P(1 + R/100 )n
= 31250(1 + 4/100 )3
= 31250 x (26/25) x (26/25) x (26/25)
= ? 35150
? CI = 35152 - 31250
= ? 3902
Correct Answer: ? 2500
Explanation:
Let required amount be ? P.
According to the question,
2916 = P (1 + R/100)2 ... (i)
and 3149.28 = P(1 + R/100)3 ... (ii)
On dividing Eq. (ii) by Eq. (i), we get
1 + R/100 = 3149.28/2916
? R/100 = (3149.28/2916) - 1
? R = (233.28/2916) x 100 = 8%
From Eq. (i),
P = (2916 x 100 x 100)/(108 x 108)
= ? 2500
Correct Answer: Rs. 600
Explanation:
Let the sum be Rs. 100 then,
S.I.= Rs.(100 x 5 x 2)/100 =Rs.10
C.l.= Rs.[100 x (1 +5/100)2] =Rs.41/4
? difference between C.I. and S.I. = Rs. (41/4-10) = Re.0.25
? 0.25 : 1.50 : : 100 : P
? P = (1.50 x 100) / 0.25 = Rs. 600
Correct Answer: Rs. 94.50
Explanation:
Principle = (100 x interest) / (time x rate)
? Sum = (100 x 90) / (2 x 10) = Rs. 450
C.I. =Rs.[ 450 x (1 + 10/100)2 - 450] = Rs. 94.50
Correct Answer: Rs. 1200
Explanation:
Let P the principle at the end of first year.
Then (P x 10 x 1)/100 =132
? P =1320
Let Q be the original principle
Then, Q + (Q x 10 x 1)/100 =1320
? Q =1200
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