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- Question
- Reena had ? 10000 with her, out of this money she lent some money to Akshay for 2 yr at 15% simple interest. She lent remaining money to Brijesh for an equal number of years at the rate of 18%. After 2 yr Reena found that Akshay had given her 360 more as interest as compared to Brijesh. The amount of money which Reena had lent to Brijesh must be
Options- A. ? 4000
- B. ? 2500
- C. ? 3500
- D. ? 4200
- Correct Answer
- ? 4000
ExplanationLet the money lent to Akshay = ? P
Then, money lent to Brijesh = ? (10000 - P) [as total amount = ? 10000]
SI for Akshay = (P x 15 x 2)/100 = 3P/10
SI for Brijesh = {(10000 - P) x 18 x 2}/100 = 9/25 (10000 - P)
According to the given condition, (3P/10) - [(9/25) x ( 10000 - P ) = 360
[as SI (Akshay) - SI (Brijesh) = 360]
? (3P/10) - 3600 + 9P/25 = 360
? 3P/10 + 9P/25 = 360 + 3600 = 3960
? 33P/50 = 3960
? P = 3960 x 50/33
? P = 6000
? The amount of money lent to Brijesh
= 10000 - 6000 ? 4000 - 1. Neeta borrowed some money at the rate of 6% per annum for the first 3 yr. at the rate of 9% per annum for the next 5 yr and a the rate of 13% per annum for the period beyond 8 yr. If she pays a total interest of ? 8160 at the and of 11 yr how much money did she borrow?
Options- A. ? 12000
- B. ? 10000
- C. ? 8000
- D. Data is inadequate Discuss
- 2. A sum of ? 1550 was lent partly at 5% and partly at 8% per annum simple interest. The total interest received after 4 yr was ? 400, The ratio of the money lent at 5% to that lent at 8% is
Options- A. 16 : 15
- B. 17 : 15
- C. 16 : 13
- D. 16 : 19 Discuss
- 3. A Principal amounts to ? 944 in 3 yr and to ? 1040 in 5 yr, each sum being invested at the same simple interest. The principal was
Options- A. ? 800
- B. ? 991
- C. ? 750
- D. ? 900 Discuss
- 4. In 4 yr. ? 6000 amounts to ? 8000. In what time at the same rate, will ? 525 amount to ? 700?
Options- A. 2 yr
- B. 3 yr
- C. 4 yr
- D. 5 yr Discuss
- 5. A certain sum at simple interest amount to ? 1350 in 5 yr and to ? 1620 in 8 yr what is the sum?
Options- A. ? 700
- B. ? 800
- C. ? 900
- D. ? 1000 Discuss
- 6. Mr. Pawan invests an amount of ? 242000 at the rate of 4% per annum for 6 yr to obtain a simple interest, later he invests the principal amount as well as the amount obtained as simple interest for another 4 yr at the same rate of interest. What amount of simple interest will be obtained at the end of the last 4 yr?
Options- A. ? 4800
- B. ? 4850.32
- C. ? 4801.28
- D. ? 4700 Discuss
- 7. A persom invests ? 12000 as fixed deposit at a bank at the rate of 10% per annum simple interest. But due to some pressing needs, he has to withdraw the entire money after 3 yr for which the bank allowed him a lower rate of interest. If he gets ? 3320 less than, what he would have got at the end of 5 yr the rate of interest allowed by bank is
Options- A. 78/9%
- B. 87/9%
- C. 78/9%
- D. 77/9% Discuss
- 8. Rajnish invested certain sum in three different schemes P, Q and R with the rates of interest 10% per annum, 12% per annum and 15% per annum, respectively. If the total interest accrued in 1 yr was ? 3200 and the amount invested in scheme R was 150% of the amount invested in scheme Q. what was the amount invested in scheme Q?
Options- A. ? 8000
- B. ? 9000
- C. ? 5000
- D. ? 3050 Discuss
- 9. Ajay takes some loan from Rashmi at the rate of 5% per annum andd after 2 yr, Ajay gave back ? 8800 to Rashmi and this way paid his whole loan. Find the interest by Ajay.
Options- A. ? 825
- B. ? 975
- C. ? 800
- D. ? 850 Discuss
- 10. The difference between the compound interest and the simple interest on a certain sum at 5% per annum for 2 years is Rs. 1.50. The sum is?
Options- A. Rs. 600
- B. Rs. 500
- C. Rs. 400
- D. Rs. 300 Discuss
Simple Interest problems
Search Results
Correct Answer: ? 8000
Explanation:
Let the sum borrowed = P
Then, according to the question,
[(P x 6 x 3)/100] + [(P x 9 x 5)/100] + [(P x 13 x 3)/100] = 8160
? (18P + 45P +39P) / 100 = 8160
? 102P/100 = 8160
? P = (8160 x 100)/102
? P = ? 8000
Correct Answer: 16 : 15
Explanation:
Let the sum lent at 5% = P
? Sum lent at 8% = (1550 - P)
Then, [(P x 5 x 4)/100] + [{(1550 - P) x 8 x 4}/100] = 400
? 20P - 32P + 1550 x 32 = 40000
? - 12P + 49600 = 40000
? - 12P = - 9600
? p = ? 800
Sum lent at 8% = 1550 - 800 = ? 750
? Required ratio = 800 : 750 = 16 : 15
Correct Answer: ? 800
Explanation:
By formula, P = (A2T1 - A1T2) / (T1 - T2)
Here, A1 = ? 944, T1 = 3
A2 = ? 1040, T2 = 5
? P = [(1040 x 3) - (944 x 5)] / (3 - 5)
= (3120 - 4720) / (-2)
= (-1600) / (-2)
= ? 800
? Principal = ? 800
Correct Answer: 4 yr
Explanation:
Amount = ? 8000
Time (T) = 4 yr; Principal (P) = ? 6000
Simple interest (SI) = (A - P)
= Amount - Principal
= 8000 - 6000 = ? 2000
Rate (R) = ?
According to the formula. SI = (P x R x T)/100
? 2000 = (6000 x R x 4)
? R = (6000 x 100)/(6000 x 4) = (25/3) %
Now, again Amount (A) = ? 700
Principle (P) = ? 525, Time (T) = ?
Rate (R) = 25/3%
Simple interest = A - P
? 700 - 525 = ? 175
Using formula, SI = (P x R x T) / 100
? 175 = [525 x (25/3) x T] / 100
? T = (175 x 100 x 3) / (525 x 25)
= 4 yr
Correct Answer: ? 900
Explanation:
Given, A1 = ? 1350, A2 =? 1620
T1 = 5 yr and T2 = 8 yr
Let principal amount be ? P.
? In time = 8 - 5 = 3 yr
Simple interest will be
1620 - 1350 = ? 270
? R = [(A2 - A1 ) x 100] / [A1 T2 - A2 T1]
= [(1620 - 1350) x 100] / [(1350 x 8) - (1620 X 5)]
= (270 x 100)/[10800 - 8100]
= 27000/2700
? R = 10%
? P = (SI x 100) / (R x T)
= (270 x 100) / (10 x 3)
= ? 900
Correct Answer: ? 4801.28
Explanation:
In the case I,
SI = (P x R x T) /100 = (24200 x 4 x 6) / 100 = ? 5808
? Amount = Principal + SI
SI = 24200 + 5808 = 30008
In the case II,
SI = (30008 x 4 x 4) / 100 = ? 4801.28
Correct Answer: 77/9%
Explanation:
Let the rate of interest allowed by bank be r%
According to the question,
[(12000 x 5 x 10)/100] - [(12000 x 3 x r)/100] = 3320
? 6000 - 360r = 3320
? 360r = 6000 - 3320 = 2680
? r = 2680/360 = 74/9%
Correct Answer: ? 5000
Explanation:
Let a, b and c be the amount invested in schemes P, Q and R, respectively.
Then, according to the question,
[(a x 10 x 1)/100] + [(b x 12 x 1)/100] + [(c x 15 x 1)/100] = 3200
? 10a + 12b + 15x = 320000 .....(i)
Now, c = 240% of b = 12b/5 ....(ii)
and c = 150% of a = 3a/2
? a = 2c/3 = (2/3 x 12/5) b = 8b/5 .....(iii)
From Eqs. (i), (ii) and (iii), we get
16b + 12b + 36b = 320000
? 64b = 320000
? b = 5000
? Sum invested in scheme Q = ? 5000
Correct Answer: ? 800
Explanation:
Here, A = ? 8800, T =2 yr, R = 5%
We know
SI = ART/(100 + RT) = (8800 x 5 x 2) / (100 + 5 x 2)
= (8800 x 10) / 110
= ? 800
Correct Answer: Rs. 600
Explanation:
Let the sum be Rs . 100 then
S.I. = Rs.(100 x 5 x 2/100)= Rs. 10
C.I = Rs. [{100 x (1 + 5/100)2} - 100] = Rs. 41/4
? Difference between C.I and S.I = Rs. (41/4 - 10) = Re. 0.25
? 0.25 : 150 : : 100 : P
? P = (1.50 x 100) / 0.25 = Rs. 600
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