Let each sum be Rs. P.
Then, [(P x 15 x 5) / 100] - [(P x 15 x 7) / 100] x 2 = 144
? 3P/4 -21P/40 = 144
? 9P/40 = 144
? P = (144 x 40) / 9 =Rs. 640
? S.I. for 3/2 years = Rs. (1067.20 - 1012) = Rs. 55.20
? S.I. for 5/2 years = Rs. 55.20 x (2/3) x (5/2) = 92
? Sum = Rs. (1012 - 92) = Rs.920
Hence, Rate = (100 x SI)/(P x T) = (100 x 92) / (920 x 5/2 ) = 4%
Let the rates be R1% and R2%.
Then, (500 x R1 x 2)/ 100 - (500 x R2 x 2)/ 100 = 2.5
? 10(R1 - R2) = 2.5
? Req difference = R1 - R2 = 0.25%
Let sum = Rs. P.
Then amount = Rs. (8P/5)
? S.I = Rs. (8P/5 - P ) = Rs.(3P/5)
? Required rate = (100 x SI) / (P x T)
= [(100 x 3P/5) / (P x 5)]% = 12%
Let sum = P and original rate = R% per annum
Then, [(P x (R + 1) x 2)/100] - [(P x R x 2)/100] = 24
? P = 1200
Let principal = P.
Then, S.I = P,
Rate (R) = 12%
Time = (100 x SI) / (R x P) = (100 x P) / (P x 12) years
= 25/3 years
= 8 years 4 months
Due to the rise in the rate of interest, annual income increases by Rs . (8 - 61/ 2) = Rs , 11/ 2
, when the capital is Rs . 100
Thus, the required capital = (100 x 2 x 4050) / 3 = Rs. 270000
Let the sum be Rs. P, SI = Rs. 600, Time = 10 years
? Rate (600 x 100) / (P x 10)%
S.I for first 5 years = Rs. (P x 5 x 6000)/(1000 x P) = Rs. 300
S.I for last 5 years = Rs. (3P x 5 x 6000)/(100 x P) = Rs. 900
Hence, total interest at the end of 10 years = 300 + 900 = Rs. 1200.
Let money lent at 12% Rs. P
Then, money lent at 121/2% = Rs. (2540 - P )
? (P x 12 x 1)/100 + {(2540 - P) x 25/2 x 1}/100 = 311.60
? 3P/25 + 2540 - P/8 = 311.60
? 24P + 25(2540 - P) = 200 x 311.60
? P = 63500 - 62320 = 1180
? [ (2000 x 8 x 1) /100] + [ (4000 x 15/2 x 1)/100] + [(1400 x 17/2 x 1) / 100] + [(2600 x R x 1)/100] = (10000 x 8.13 x 1) / 100
? 160 + 300 + 119 + 26R = 813
? 26R = 234
? R = 9%
If interest is 40% of the principal then time = 5 years.
So, when interest would be equal to 100% of the principal time would be
= (100/40) x 5 years = 12.5 years
= 12 yr 6 months
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