Given, T1 = 21/2 yr, T2 = 4 Yr
According to the question.
[P + (P x R x 4)/100] - [P + (P x R x 2.5)/100] = 1067.20 - 1012 = 55.2
? (1.5 x P x R)/100 = 55.2
? PR = (552 x 100) / 15 = 3680
For 4 yr.
SI = PRT/100 = (3680 x 4)/100 = ? 147.2
? Sum (P) = 1067.2 - 147.2 = ? 920
We have, PR = 3680
? R = 3680/P = 3680/920 = 4%
.02 =(2/100) x 100% =2%
Let N / 11 = 233
Then, N = 233 x 11 = 2563
? Missing digit is 5.
121012 = 12 x 10084 + 4
? remainder = 4
We have the important relation, More work, More time (days)
? A piece of work can be done in 6 days.
? Three times of work of same type can be done in 6 x 3
= 18 days
? = 750.0003 ÷ 19.999
? ? ? 750 ÷ 20
? ? ? 375 ? 38
Subtract 20, 25, 30, 35, 40, 45 from successive numbers. So 0 is wrong.
NA
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