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- Question
- Yogesh borrowed Rs. 12000 at simple interest for 5 years, If he paid Rs. 3600 as simple interest after 5 years, What is the rate of interest per cent per annum?
Options- A. 5
- B. 8
- C. 10
- D. 6
- Correct Answer
- 6
ExplanationRate = [(interest x 100) / (Principal x Time)] %
= (3600 x 100) / (12000 x 5)
= 6 % - 1. Ashok took a loan of Rs. 15000 for 3 years at simple interest . If the total interest paid is Rs. 2700. What is the rate of interest per annum?
Options- A. 18
- B. 5.4
- C. 9
- D. 6 Discuss
- 2. What annual payment will discharge a debt of Rs. 580 due in 5 years, the rate being 8% per annum?
Options- A. Rs. 166.40
- B. Rs. 65.60
- C. Rs. 100
- D. Rs. 120 Discuss
- 3. At simple interest, a sum doubles after 20 years. The rate of interest per annum is?
Options- A. 5%
- B. 10%
- C. 12%
- D. Data inadequate Discuss
- 4. The simple interest at R% for R years will be Rs. R on a sum of?
Options- A. Rs. R
- B. Rs. 100R
- C. Rs. .(100/R)
- D. Rs. (100/R2) Discuss
- 5. A sum of money at simple interest amounts to Rs. 2240 in 2 years and Rs. 2600 in 5 years. The sum is?
Options- A. Rs. 1880
- B. Rs. 2000
- C. Rs. 2120
- D. Data inadequate Discuss
- 6. If a sum of money double itself in 20 years. What is the rate of simple interest per cent per year?
Options- A. 4%
- B. 8%
- C. 5%
- D. 10% Discuss
- 7. Mr. Patel borrowed Rs. 8000 from Mr. Chobey at simple interest. After 2 years he paid Rs. 800 more than what be borrowed and thus cleared the loan. What was the rate of interest?
Options- A. 6
- B. 8
- C. 5
- D. None of these Discuss
- 8. Rs. 4200 amounts to Rs. 5712 in 4 years. If rate of interest is increased by 3%. What will be the amount?
Options- A. Rs. 6372
- B. Rs. 4000
- C. Rs. 6216
- D. Rs. 3000 Discuss
- 9. In how many years, a sum will become four times itself at the rate of 12% per annum?
Options- A. 28 yr
- B. 25 yr
- C. 22 yr
- D. 27 yr Discuss
- 10. At simple interest of 5%, 6% and 8% for three consecutive years, the interest earned is ? 760. find the principle.?
Options- A. ? 4600
- B. ? 3200
- C. ? 4000
- D. ? 3600 Discuss
Simple Interest problems
Search Results
Correct Answer: 6
Explanation:
? Rate = [(interest x 100) / (Principal x Time) ] %
? Rate = (2700 x 100) / (15000 x 3) %
? Rate = 6%
Correct Answer: Rs. 100
Explanation:
Let the annual installment be Rs. P
Then, [P + (P x 4 x 8)/100] + [P + (P x 3 x 8) / 100] + [P + (P x 2 x 8)/100 ] + [ P + (P x 1 x 8)/100] + P = 580
? 33P/25 + 31P/25 + 29P/25 + 27P/25 + P = 580
? (120 + 25)P = 580 x 25
? P = 100
Correct Answer: 5%
Explanation:
Let sum = P, then SI = P and Time = 20 years
? Required rate = (100 x SI)/(P x T) = (100 x P) / (P x 20) = 5% per annum
Correct Answer: Rs. .(100/R)
Explanation:
Sum = (100 x SI) / (R x T)
= (100 x R) / (R x R)
= Rs. 100/R
Correct Answer: Rs. 2000
Explanation:
S.I for 3 years = Rs. (2600 - 2240) = Rs . 360
S.I for 2 years = Rs. (360/3 x 2) = Rs. 240
? Required sum = Rs . (2240 - 240) = Rs. 2000
Correct Answer: 5%
Explanation:
Let the principal = Rs. P
? Amount = Rs. 2P
? Interest = 2P - P = Rs.P
? Rate = (interest x 100) / (Principal x 20) = (P x 100) / (P x 20) = 5%
Correct Answer: 5
Explanation:
Rate = (Interest x 100) / (Principal x Time)
= (800 x 100) / (8000 x 2)
= 5%
Correct Answer: Rs. 6216
Explanation:
S.I = Principal x Rate x Time / 100
? Amount - Principal = Principal x Rate x Time / 100
? 5712 - 4200 = (4200 x Rate x 4) /100
? 1512 = 42 x 4 x Rate
Rate = 1512 / (42 x 4) = 9%
On increasing 3%, new rate of interest = 9 + 3 = 12%
Simple interest on new rate = (4200 x 12 x 4) / 100 =Rs. 2016
Amount = Principal + Interest = 4200 + 2016 = Rs. 6216
Correct Answer: 25 yr
Explanation:
Let the sum be ? P .
Then, SI = 4P - P = ? 3P
(P x 12 x T)/100 = 3P
? T = (3 x 100)/12 = 25 yr
Correct Answer: ? 4000
Explanation:
Let the principle be ? P .
Then,
(P x 1 x 5)/100 + (P x 1 x 6)/100 + (P x 1 x 8)/100 = 760
? 5P/100 + 6P/100 + 8P/100 = 760
? 19P = 760 x 100
? P = (760 x 100)/19 = ? 4000
Hence, the principle is ? 4000.
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