Difficulty: Easy
Correct Answer: Nonlinear
Explanation:
Introduction / Context:
Accurate classification of components guides how we model and simulate circuits. The current–voltage (I–V) curve of a diode determines its behavior in rectifiers, clippers, clamps, logic protection, and signal detection.
Given Data / Assumptions:
Concept / Approach:
A linear device exhibits a proportional I–V relationship (straight line through the origin), characterized by a constant resistance. A diode’s I–V curve is exponential in forward bias with a threshold-like knee and has high resistance in reverse bias up to breakdown, making the relationship decidedly nonlinear.
Step-by-Step Solution:
Recall diode equation: i ≈ I_S * (e^(v/(nV_T)) − 1) in forward bias.Recognize this is not a straight line; conductance changes with operating point.Conclude the device is nonlinear over its operating range.Select “Nonlinear.”
Verification / Alternative check:
Plotting I–V on linear axes shows curvature; small-signal models linearize only locally around a bias point with dynamic resistance r_d, confirming global nonlinearity.
Why Other Options Are Wrong:
A: “Bilateral” refers to symmetric bidirectional behavior; diodes conduct asymmetrically. B: Linear would require constant slope, which a diode lacks. D: “Unipolar” describes certain transistor transport mechanisms, not the diode’s I–V classification. E: Not applicable because a correct option exists.
Common Pitfalls:
Assuming near-constant forward drop makes the diode “linear”—that is a convenient approximation, not a true linear relationship; confusing conduction directionality with linearity.
Final Answer:
Nonlinear
Discussion & Comments