Difficulty: Easy
Correct Answer: The propagation delay in ns is multiplied by the power dissipation in mW.
Explanation:
Introduction / Context:
The speed–power product (SPP) is a widely used figure of merit to compare logic families. It captures the trade-off between how fast a gate switches (propagation delay) and how much power it consumes. A lower SPP indicates better efficiency: faster operation per unit of power.
Given Data / Assumptions:
Concept / Approach:
Multiply the typical propagation delay (ns) by the typical power dissipation (mW). The product has units of nJ/s? Interpreted more practically, ns * mW = picojoules (since mW = mJ/s and ns scales time), which reflects the energy per switching event under certain simplifying assumptions. Families with lower SPP achieve shorter delays with less power.
Step-by-Step Solution:
Verification / Alternative check:
Example: A gate with tp = 10 ns and PD = 10 mW has SPP = 100 ns·mW (≈ 100 pJ). A gate with tp = 5 ns and PD = 40 mW has SPP = 200 ns·mW—faster but less efficient by this metric.
Why Other Options Are Wrong:
Common Pitfalls:
Final Answer:
The propagation delay in ns is multiplied by the power dissipation in mW.
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