Difficulty: Medium
Correct Answer: 87.9 dB
Explanation:
Introduction:
Common-mode rejection ratio (CMRR) quantifies how well a differential amplifier suppresses signals that are common to both inputs relative to signals that are different between them. A high CMRR is critical for rejecting power-line hum, reference shifts, and electromagnetic interference in sensor front-ends and instrumentation systems.
Given Data / Assumptions:
Concept / Approach:
CMRR (ratio) is defined as A_d / A_cm. To express it in decibels, use CMRR_dB = 20 * log10(A_d / A_cm). A larger ratio means the amplifier strongly prefers differential signals and rejects common disturbances.
Step-by-Step Solution:
Compute ratio: CMRR = A_d / A_cm = 50,000 / 2 = 25,000Convert to dB: CMRR_dB = 20 * log10(25,000)Evaluate log10(25,000) ≈ 4.39794CMRR_dB ≈ 20 * 4.39794 ≈ 87.9588 dBRounded to one decimal place: 87.9 dB
Verification / Alternative check:
As a quick estimate, 20 * log10(10,000) = 80 dB and 20 * log10(2.5) ≈ 8 dB; total ≈ 88 dB, consistent with the precise calculation. The resulting value is typical for general-purpose op-amps and below that of precision instrumentation amplifiers.
Why Other Options Are Wrong:
Common Pitfalls:
Final Answer:
87.9 dB
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