Difficulty: Hard
Correct Answer: 641
Explanation:
Introduction:
This question tests comparing compound interest under different compounding frequencies for the same annual rate and time. More frequent compounding produces a higher amount because interest is added sooner and then earns interest again within the year. Here we compare quarterly compounding versus annual compounding for 1 year at a high rate of 40%, which makes the difference noticeable.
Given Data / Assumptions:
Concept / Approach:
Compute CI in each case and subtract. For annual compounding over 1 year: amount = P * (1 + 40/100). CI = amount - P. For quarterly compounding: quarterly rate = 40%/4 = 10%, number of quarters = 4, amount = P * (1 + 10/100)^4 = P * (1.1)^4. CI is again amount minus principal. Difference is CI_quarterly - CI_annual.
Step-by-Step Solution:
Annual compounding amount = 10000 * 1.40 = 14000
CI (annual) = 14000 - 10000 = 4000
Quarterly rate = 10%
Quarterly compounding factor = (1.1)^4
(1.1)^2 = 1.21, so (1.1)^4 = 1.21^2 = 1.4641
Quarterly amount = 10000 * 1.4641 = 14641
CI (quarterly) = 14641 - 10000 = 4641
Difference = 4641 - 4000 = 641
Verification / Alternative check:
Since quarterly compounding is more frequent, the difference must be positive. The computed difference ₹641 is consistent and matches the gap between 1.4641P and 1.40P for P=10000.
Why Other Options Are Wrong:
461, 463, and 346 are too small compared to the correct compounding gap at 40% annual. 400 matches neither CI difference nor any correct intermediate step.
Common Pitfalls:
Using 40% as quarterly rate, using only one quarter instead of four, or subtracting annual amount from quarterly interest without consistently converting to CI first.
Final Answer:
The required difference is ₹641.
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