Compound vs Simple Interest — Use 2-year difference to recover principal: For a certain principal, the difference between the 2-year compound interest and the 2-year simple interest at 8% per annum is ₹ 32. Find the principal.

Difficulty: Easy

Correct Answer: ₹ 5000

Explanation:


Introduction / Context:
The difference between compound interest (CI) and simple interest (SI) over exactly two years at the same annual rate is a classic identity. It isolates the “extra” interest-on-interest that CI accumulates. This lets us back-solve the principal without separately knowing the amount.



Given Data / Assumptions:

  • Annual rate r = 8% = 0.08
  • Time t = 2 years
  • CI − SI over 2 years = ₹ 32
  • Principal P unknown


Concept / Approach:
For two years at rate r (decimal), CI − SI = P * r^2. This follows from CI for 2 years = P[(1 + r)^2 − 1] = P(2r + r^2), SI for 2 years = P(2r), hence the difference is P r^2.



Step-by-Step Solution:

Use identity: CI − SI = P r^2.Substitute: 32 = P * (0.08)^2 = P * 0.0064.Solve P = 32 / 0.0064 = 5000.


Verification / Alternative check:

Check numerically: On ₹ 5000, SI(2y, 8%) = 5000 * 0.16 = 800; CI(2y) adds r^2 * P = 0.0064 * 5000 = 32 more ⇒ 832. Difference 32 (matches).


Why Other Options Are Wrong:

  • ₹ 5250, ₹ 5550, ₹ 6000, ₹ 4800 do not satisfy 32 = P * 0.0064.


Common Pitfalls:

  • Using r as “8” instead of 0.08 in the formula.
  • Applying the identity to durations other than 2 years; it is specific to 2 years in this neat form.


Final Answer:
₹ 5000.

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