Difficulty: Medium
Correct Answer: ""=="" performs loose equality with type coercion, while ""==="" performs strict equality without converting the operands to a common type.
Explanation:
Introduction / Context:
JavaScript provides two main equality operators: the double equals (==) and the triple equals (===). They are often a source of confusion because they look similar but follow different rules, especially when the operands have different types. Understanding the difference is essential for writing predictable, bug free comparisons.
Given Data / Assumptions:
Concept / Approach:
The double equals operator == attempts to convert operands to a common type before comparing them. For example, "5" == 5 evaluates to true because the string "5" is converted to the number 5. This is called type coercion. The triple equals operator ===, on the other hand, does not perform such conversion. It first checks whether the operands have the same type; if they do not, the result is false. If they do, it compares them as values of that type. Using === avoids many surprising results caused by automatic coercion.
Step-by-Step Solution:
Verification / Alternative check:
Experimenting in the console with pairs like null == undefined (which is true) and null === undefined (which is false) clearly shows that == has special coercion rules, while === does not. Many style guides recommend using === and !== for most comparisons to avoid the subtle behaviors of ==.
Why Other Options Are Wrong:
Common Pitfalls:
A common pitfall is relying on == and accidentally accepting values like "" (empty string), 0, or false as equivalent. Another mistake is assuming === is always slower; in practice, the difference is negligible compared to the gains in code clarity. Most modern JavaScript code bases and linters encourage consistent use of === unless a specific, well understood coercion is desired.
Final Answer:
The correct choice is ""=="" performs loose equality with type coercion, while ""==="" performs strict equality without converting the operands to a common type. because this precisely captures the core behavioral difference between the two operators in JavaScript.
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