Difficulty: Easy
Correct Answer: any one of the above
Explanation:
Introduction / Context:
The diagram factor accounts for the discrepancy between the ideal (theoretical) and the actual indicator diagram caused by throttling, condensation, leakage, and valve timing. It is used to correct theoretical work or mean effective pressure (MEP) to more closely match reality.
Given Data / Assumptions:
Concept / Approach:
Because work per cycle equals the area under the p–v curve, and MEP is work divided by piston displacement, the ratios of areas, works, and MEPs are numerically identical. Therefore, any of these ratios can serve as the definition of diagram factor for a given cycle and cylinder.
Step-by-Step Solution:
Relate work to area: W_actual ∝ Area_actual; W_theoretical ∝ Area_theoretical.Define MEP: MEP = Work / Displacement; the displacement cancels in the ratio.Conclude equivalence: Area ratio = Work ratio = MEP ratio.
Verification / Alternative check:
Check units: all ratios are dimensionless and bounded between 0 and 1.
Why Other Options Are Wrong:
Options (a), (b), and (c) are each correct individually; hence 'any one of the above' captures the full, equivalent definitions.
Common Pitfalls:
Treating diagram factor as a universal constant; it depends on operating conditions and valve setting.
Final Answer:
any one of the above
Discussion & Comments