Relative ordering by weight — five persons A, B, C, D, E A, B, C, D and E are arranged in descending order of weight from the top (heaviest at the top). A is third; E is between D and A; C and D are not at the top. Who is second?

Introduction / Context:This is a positional logic puzzle with constraints that pin down an exact arrangement.

Given Data / Assumptions:

• Positions 1..5 from top (1 = heaviest).
• A is at position 3.
• E is between D and A.
• C and D are not at position 1.

Concept / Approach:Test placements consistent with “E between D and A,” given A is fixed at 3. This yields two structural possibilities: (i) D–E–A (positions 1–2–3) or (ii) A–E–D (positions 3–4–5). Apply the “not at the top” bans to eliminate impossible cases.

Step-by-Step Solution:Case (i): D at 1, E at 2, A at 3 ⇒ violates “D is not at the top.” Reject.Case (ii): A at 3, E at 4, D at 5 ⇒ satisfies the “between” condition and the bans.Remaining persons B and C fill positions 1 and 2, but C cannot be at top (position 1), so B=1 and C=2.

Verification / Alternative check:The final order (from top): B, C, A, E, D satisfies all statements.

Why Other Options Are Wrong:Any other second place fails the “not at top” or “between” constraints.

Common Pitfalls:Putting D at top in the first arrangement and overlooking the explicit ban.

Final Answer:C