Inherited member availability: If the base class defines a member function func(), and the derived class does not define a function with that name, can an object of the derived class call func()? Provide the correct evaluation.

Introduction / Context: The claim suggests a derived object cannot access a base member unless the derived redeclares it. In C++, members of the base are part of the derived object as long as they are not hidden and remain accessible under the chosen inheritance mode (public/protected/private) and access level (public/protected).

Given Data / Assumptions:

• Base declares a function func() that is accessible to Derived (e.g., public).
• Derived does not declare another func().
• Use public inheritance for typical behavior.

Concept / Approach: With public inheritance, public base members remain public in the derived interface. Therefore, calls like Derived d; d.func(); are perfectly valid. Virtual is not required to call the function; virtual only affects which implementation runs when calling through a base interface and enabling overriding. If Derived declared another overload with the same name, name hiding could affect lookup, but in the scenario stated, no such overload exists.

Step-by-Step Solution:

Verification / Alternative check: Change inheritance to private: public members of Base become private within Derived and may not be callable from outside via a Derived object, but still callable inside Derived’s own member functions — showing access control matters, not the existence of an override.

Why Other Options Are Wrong:

• “Cannot call unless redefined”: incorrect; inheritance exposes the base implementation.
• “Only if virtual”: virtuality is not required for direct calls.
• “Requires base scope qualification”: not necessary unless hidden by another declaration.

Common Pitfalls: Confusing overriding with availability; and conflating access specifiers with the need to redeclare symbols in the derived class.

Final Answer: Incorrect statement — the derived object can call func() if it is accessible via inheritance.