Difficulty: Easy
Correct Answer: Increases
Explanation:
Introduction / Context:
Thermal sterilization and pasteurization are quantified using death-kinetics metrics. One convenient measure of total microbial kill is the lethality or “del factor” Δ, which accumulates over the heating, holding, and cooling phases. Understanding how Δ relates to the surviving cell count is critical for setting time–temperature schedules that achieve target sterility assurance levels.
Given Data / Assumptions:
Concept / Approach:
For log-linear inactivation, the relationship between lethality Δ and survivor numbers is monotonic. A useful form is Δ ∝ ln(N0/N_f) (natural logs) or Δ_10 ∝ log10(N0/N_f) (decimal reductions). Smaller N_f (fewer survivors) means a larger ratio N0/N_f, hence a larger Δ, i.e., more lethal effect delivered.
Step-by-Step Solution:
Start with survivor equation: N_f = N0 * exp(−k * t_equiv).Rearrange: ln(N0/N_f) = k * t_equiv ≡ Δ (when expressed at a reference temperature).Observe dependency: as N_f decreases, ln(N0/N_f) increases.Therefore, the del factor Δ increases when the final number of cells decreases.
Verification / Alternative check:
Decimal reduction language: a 1-log reduction (10×) raises Δ_10 by 1; going from 10^6 to 10^0 survivors is a 6-log reduction, clearly indicating greater lethality with lower N_f.
Why Other Options Are Wrong:
“Decreases” or “remains constant” contradict the monotonic relationship between Δ and N_f.
“Becomes zero” would only occur if there were no lethal exposure or N_f = N0.
Common Pitfalls:
Final Answer:
Increases
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