Arrange four words by decreasing total vowel count (ties broken by dictionary order): Assassination, Rejuvenation, Mississippi, Acrimonious.

Introduction / Context:
The task ranks words by the number of vowels, counting each occurrence. When two or more words have the same total, alphabetical order decides among them.

Given Data / Assumptions:

• Words: Assassination, Rejuvenation, Mississippi, Acrimonious.
• Vowels: a, e, i, o, u (y not counted).

Concept / Approach:
Count vowels with multiplicity for each word. Then sort descending by that count. If counts tie, sort those tied words alphabetically.

Step-by-Step Solution:
Assassination → vowels = a(3) + i(2) + o(1) = 6.Rejuvenation → vowels = e(2) + u(1) + a(1) + i(1) + o(1) = 6.Acrimonious → vowels = a(1) + i(2) + o(2) + u(1) = 6.Mississippi → vowels = i(4) = 4.Tie on 6: alphabetical order → Acrimonious, Assassination, Rejuvenation.Append Mississippi (4) at the end.

Verification / Alternative check:
Manual recounts or a quick script yield the same totals and tie-break.

Why Other Options Are Wrong:
They misorder the tie group or place Mississippi above words with more vowels.

Common Pitfalls:
Forgetting that each vowel occurrence counts; overlooking the alphabetical tie-break rule.

Final Answer:
Acrimonious, Assassination, Rejuvenation, Mississippi