Using the standard Gregorian calendar, what day of the week fell on 16 June 1993?

Introduction / Context:
Day of the week questions for a specific historical date test your ability to work with calendar arithmetic. Instead of memorising answers, you can systematically apply a method such as counting odd days from a known reference date or using a standard day of week formula. Here we must find the weekday on 16 June 1993.

Given Data / Assumptions:
- Date required = 16 June 1993. - Calendar system = Gregorian calendar. - Leap year rule: divisible by 4, except century years must be divisible by 400. - We need only the weekday name, not the number of days between dates.

Concept / Approach:
One common approach is to count odd days from a reference year such as 1 January 1900 or 1 January 2000 and then add the contribution of months and days. Odd days are left over when total days are divided by 7. Another practical approach in exams is to use a well known base date, compute the number of days up to the target date, and then take the remainder modulo 7 to determine the weekday. We apply this logic to reach the correct weekday for 16 June 1993.

Step-by-Step Solution:
Step 1: Consider years up to 1992 complete. Count total days from a chosen base year to 1 January 1993, converting them into odd days. Step 2: Determine how many leap years and normal years occur in that span and compute total extra days modulo 7. Step 3: From 1 January 1993, add days for each month up to June. January has 31 days, February 1993 has 28 days because 1993 is not a leap year, March 31 days, April 30, May 31, and finally 16 days of June. Step 4: Sum these monthly and daily contributions and again reduce modulo 7, adding to the year level odd days. Step 5: Interpreting the final remainder through the weekday mapping (for example, 0 for Sunday, 1 for Monday, and so on) gives the day for 16 June 1993. Step 6: On performing the full calculation correctly, the remainder corresponds to Wednesday.

Verification / Alternative check:
A reliable alternative is to compare with a known date near 1993 for which the weekday is well documented and count forwards or backwards. Many standard references and verified algorithms confirm that 16 June 1993 was a Wednesday. You can also verify using the Zellers congruence style formula, which consistently yields the weekday as Wednesday when input with day 16, month June, and year 1993.

Why Other Options Are Wrong:
- Monday, Friday, Saturday, and Thursday correspond to different remainders when total days are divided by 7 and therefore do not match the computed result. - Small mistakes in counting leap years or month day totals might lead to one of these distractor answers, but careful work always leads to Wednesday.

Common Pitfalls:
Typical errors include treating 1992 or 1993 incorrectly as leap years, miscounting days in February, or mixing up month codes in formula based methods. Another frequent issue is forgetting to apply the correct century code when using congruence formulas. To avoid these problems, work step by step, double check leap year logic, and always reduce large day counts modulo 7.

Final Answer:
The day of the week on 16 June 1993 was Wednesday.