Given the declarations below, which statement correctly assigns the value 33 to variable c in C#? byte a = 11, b = 22, c;

Introduction / Context:C# applies integral promotion rules to arithmetic with small integer types (byte, sbyte, short). Understanding these rules is crucial to avoid compilation errors and unintended results.

Given Data / Assumptions:

• a and b are bytes with values 11 and 22.
• We need c (also a byte) to become 33.
• Arithmetic on bytes promotes operands to int.

Concept / Approach:In C#, expressions like a + b where a and b are bytes are evaluated as ints. Assigning the int result back to a byte requires an explicit cast after the addition. Casting operands individually does not help because the addition result is still promoted to int; the cast must be applied to the entire sum.

Step-by-Step Solution:

Verification / Alternative check:Attempt to compile each option: only c = (byte)(a + b); compiles cleanly and yields 33.

Why Other Options Are Wrong:

• B: (byte)a + (byte)b still promotes to int; missing final cast to byte.
• C/D: Casts to int produce an int result; cannot assign to byte without another cast.
• E: Implicit narrowing conversion is not allowed; compile-time error.

Common Pitfalls:Assuming per-operand casts prevent result promotion; in C#, the operator result type controls assignment requirements.

Final Answer:c = (byte) (a + b);