Difficulty: Easy
Correct Answer: A reference variable is an alias for an existing variable, must be initialized when declared, and thereafter refers to the same storage location.
Explanation:
Introduction / Context:
References are a core feature of C++ that support safer parameter passing and operator overloading. Unlike pointers, references are designed to behave almost like alternate names for existing objects. This question checks whether you understand the basic properties of reference variables and how they differ from pointers or independent copies.
Given Data / Assumptions:
Concept / Approach:
A reference variable is an alias: another name for the same memory location. When you declare int &r = x;, r and x refer to the same object, so any change through r is visible through x and vice versa. References must be initialized when declared, and they cannot later be reseated to refer to a different variable. This behaviour makes references ideal for implementing pass by reference semantics and user friendly operator overloading syntax in C++.
Step-by-Step Solution:
Step 1: Declare an int x = 10; as the original variable.
Step 2: Create a reference int &r = x; which binds r as an alias for x.
Step 3: When you execute r = 20;, the assignment modifies x because they share the same storage.
Step 4: Reading x now yields 20, confirming that r and x refer to the same object.
Step 5: You cannot later do something like int y = 30; r = y; to reseat r; that statement assigns y's value to x, not to r's binding.
Verification / Alternative check:
If you print the addresses &x and &r using cout, you will see they are identical, confirming that no new object was created. If you instead used a pointer int *p = &x;, then *p is used to access the value, and p can later point to another int. This contrast verifies that references are fixed aliases while pointers are variables that can change what they point to.
Why Other Options Are Wrong:
Option B describes pointer behaviour, not references, because references cannot be reseated after initialization. Option C is wrong because references are not automatically destroyed after each statement; they follow normal scope rules. Option D is incorrect since references provide direct access to the underlying value rather than just being constant address holders.
Common Pitfalls:
Programmers sometimes forget that assigning to a reference assigns to the underlying variable, which can cause surprising side effects. Another pitfall is returning references to local variables from functions, which results in dangling references. Understanding references as stable aliases rather than independent variables is essential for writing safe and clear C++ code.
Final Answer:
A reference variable is an alias for an existing variable, must be initialized when declared, and thereafter refers to the same storage location.
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