C++ inheritance with float and char: what does the following print after casting a computed float to char and then to int? #include<iostream.h> class CuriousTabBase { public: float x; }; class CuriousTabDerived : public CuriousTabBase { public: char ch; void Process() { ch = (int)((x = 12.0) / 3.0); } void Display() { cout << (int)ch; } }; int main() { CuriousTabDerived *objDev = new CuriousTabDerived; objDev->Process(); objDev->Display(); return 0; }

Introduction / Context:This question verifies understanding of casts and character storage. A float is computed, cast to int, stored in a char, and later printed after casting the char back to int.

Given Data / Assumptions:

• x is set to 12.0 and divided by 3.0 ⇒ 4.0.
• Result is cast to int (→ 4) and assigned to ch.
• Display() prints (int)ch, not the character literal.

Concept / Approach:Because the integer value 4 is stored in the char and then printed as an integer, the output is the number 4, not the ASCII code for the glyph '4' (which would be 52).

Step-by-Step Solution:Compute 12.0 / 3.0 = 4.0.Cast to int ⇒ 4; assign to ch.Print (int)ch ⇒ 4.

Verification / Alternative check:Compare cout << ch (character) versus cout << (int)ch (integer value) to see the difference.

Why Other Options Are Wrong:Options B/E confuse the numeric value 4 with the ASCII code for the character '4'. Options C/D are inconsistent with the explicit calculation and casts.

Common Pitfalls:Assuming characters always print as glyphs; an explicit cast to int prints the numeric value.

Final Answer:The program will print the output 4.